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Karolina [17]
3 years ago
12

NO LINKS I WILL REPORT YOU.

Mathematics
1 answer:
andrezito [222]3 years ago
7 0

Answer:

0 ≤ x < 1.12 and 34.18 < x ≤ 39.87

Step-by-step explanation:

Not my answer Props to this guys: brainly.com/question/14438192

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The high school leadership team is having a car wash. They charge $5.50 for large cars and $4.00 for small cars . They had a suc
11Alexandr11 [23.1K]

Answer: 56 large cars and 86 small cars.

Step-by-step explanation:

Let's call:

l: the number of large cars.

s: the number of small cars.

Then, you can set up the following system of equations:

\left \{ {{l+s=142} \atop {5.50l+4.0s=652.50}} \right.

You can use the Elimination Method:

- Multiply the first equation by -4.0

- Add both equations.

- Solve for l.

\left \{ {{-4.0l-4.0s=-568} \atop {5.50l+4.0s=652.50}} \right.\\--------\\1.5l=84.5

l≈56

Substitute l=56 into one of the original equations and solve for <em>s:</em>

<em> </em>56+s=142\\s=142-56\\s=86

3 0
3 years ago
A water cooler holds 15 liters of sports drink. Approximately how many gallons is this? (1 gallon = 3.785 liters) HELP ME PLEASE
Julli [10]

Answer:

Approximately 56.775 gallons

Step-by-step explanation:

15 x 3.785

=56.775

6 0
3 years ago
Becky put $100 into in the account to use for school expenses. The account earns 11% interest, compounded annually. How much wil
Mnenie [13.5K]

Answer: $187 will be in the account after 6 years.

Step-by-step explanation:

We would apply the formula for determining compound interest which is expressed as

A = P(1+r/n)^nt

Where

A = total amount in the account at the end of t years

r represents the interest rate.

n represents the periodic interval at which it was compounded.

P represents the principal or initial amount deposited

From the information given,

P = $100

r = 11% = 11/100 = 0.11

n = 1 because it was compounded once in a year.

t = 6 years

Therefore,.

A = 100(1 + 0.11/1)^1 × 6

A = 100(1 + 0.11)^6

A = 100(1.11)^6

A = $187

5 0
3 years ago
3) show that the two lines with the given slopes are parallel, perpendicular neither. My₁ = 3/4 M₂ = 12/16 . solve it by showing
Jet001 [13]

Parallel lines have equal slope so

  • M1-M2=0

Lets check

  • M1=3/4
  • M2=12/16=3/4

Now

  • M1-M2
  • 3/4-3/4
  • 0

Lines are parallel

8 0
2 years ago
Read 2 more answers
Let $f(x) = 2x^2 + 3x - 9,$ $g(x) = 5x + 11,$ and $h(x) = -3x^2 + 1.$ Find $f(x) - g(x) + h(x).$
Viefleur [7K]

QUESTION 1

Given that:

f(x)=2x^2+3x-9,

g(x)=5x+11,

and

h(x)=-3x^2+1

Then;

f(x)-g(x)+h(x)=2x^2+3x-9-(5x+11)+(-3x^2+1)

f(x)-g(x)+h(x)=2x^2+3x-9-5x-11-3x^2+1

Group similar terms;

f(x)-g(x)+h(x)=2x^2-3x^2+3x-5x-11-9+1

Simplify;

f(x)-g(x)+h(x)=-x^2-2x-19

QUESTION 2

Given that;

f(x)=4x-7.

g(x)=(x+1)^2

and

s(x)=f(x)+g(x)

Substitute the functions;

s(x)=4x-7+(x+1)^2

Substitute x=3

s(3)=4(3)-7+(3+1)^2

s(3)=12-7+(4)^2

s(3)=5+16

s(3)=21

QUESTION 3

Given:

f(x)=3x+2

g(x)=x^2-5x-1

f(g(x))=f(x^2-5x-1)

This implies that;

f(g(x))=3(x^2-5x-1)+2

Expand the parenthesis;

f(g(x))=3x^2-15x-3+2

f(g(x))=3x^2-15x-1

QUESTION 4

The given function is;

f(x)=3(x-6)^2+1

Let

y=3(x-6)^2+1

\Rightarrow y-1=3(x-6)^2

\Rightarrow \frac{y-1}{3}=(x-6)^2

\Rightarrow \sqrt{\frac{y-1}{3}}=x-6

\Rightarrow x=6+\sqrt{\frac{y-1}{3}}

The range is:

\frac{y-1}{3}\ge0

y-1\ge0

y\ge1

The interval notation is;

[1,+\infty)

6 0
4 years ago
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