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postnew [5]
3 years ago
6

Y = 2x + 3 2y = 4x + 6 The system of equations has _____ solution(s).

Mathematics
1 answer:
Len [333]3 years ago
6 0
Dividing the 2nd equation by 2 gives y=2x + 3 which is the same as the too
p line. any answer to one of them is obviously an answer to the other so there are infinitely many solutions
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I really need help, please? :)
son4ous [18]
124* or 56* good luck
6 0
3 years ago
WILL GIVE THE BRAINLIEST. PLEASE HELP.
stiks02 [169]

Answer:

300 miles.

Step-by-step explanation:

Distance = Rate * Time

We know the rate, 80 miles per hour.

We know the time, 3.75 hours.

As these use the same time unit, hours, we don't need to change any values.

We can just put these values into the formula:

d=r*t

d=80*3.75=300

Answer: 300 miles.

3 0
3 years ago
Read 2 more answers
Choose all that define a rectangle in the coordinate plane by the four given points.
inysia [295]

Answer:

The answer is A(-3,-4) B(-1,2) C(2,1) D(0,-5)

Step-by-step explanation:

4 0
3 years ago
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Evaluate the following expression:<br> -X- 6x + 10 when x = 5
BigorU [14]

Answer:

-25

Step-by-step explanation:

Evaluate -x - 6 x + 10 where x = 5:

-x - 6 x + 10 = -5 - 6×5 + 10

-6×5 = -30:

-5 + -30 + 10

-5 - 30 + 10 = 10 - (5 + 30):

10 - (5 + 30)

5 + 30 = 35:

10 - 35

10 - 35 = -(35 - 10):

-(35 - 10)

| 3 | 5

- | 1 | 0

| 2 | 5:

Answer:  -25

8 0
3 years ago
can someone answer these 2 questions asap and thank you its also double the points because it 2 questions ;)
Juli2301 [7.4K]

9:

r\leq15.5 (not the one with the line under it i just couldnt find the one that didnt have the line under it)

for the graph, put 16 on the right side and label the lines right to left 16 15.5 14 14.5 etc. Put an open circle on the 15.5 line. then make an arrow pointing to the left.

10:

80\leqp+64

This is because she needs 80 points OR MORE and (p represents the points) she already has 64. She needs 80 to be less than or equal to the amount of points earned.

The solution is 16\leqp because 80-64=16 and p is needs to be greater than or equal to 16

7 0
3 years ago
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