U = (-2,3)
V = (3,0)
midpoint of UV
= ( (3-2)/2 , (3+0)/2 )
= ( 1/2 , 3/2)
= ( 0.5 , 1.5)
X = (0.5 , 1.5) [from fig]
midpoint of UV = X
W= (-2,-3)
V =( 3.0)
Y = ( (-2+3)/2 , (-3+0)/2 )
= (0.5 , - 1.5)
Y = ( 0.5 , -1.5) [ from fig ]
Y is the midpoint of WV
by midpoint theorem ,
UW = 2( XY )
Answer:
31.25
Step-by-step explanation:
Answer:
512 ft is the length of the field
Step-by-step explanation:
Firstly, we need to know the area of the field. We have confirmed this to be rectangular. Since it’s a rectangular field, the area of the field can be obtained by multiplying the length of the field by the breadth or width of the field.
Mathematically A = L * W
In the question, A = 210,944 ft^2
L= ? and W = 412ft
In essence, we are trying to calculate the value for the length of the field
L = A/W
L = (210,944)/412 = 512ft
Answer:
40 grams
Step-by-step explanation:
y * 25% + x * 10% = 120 * 15%
x = 120 - y
(120-y) * 10% = x * 10%
y * 25% + (120 - y ) * 10% = 120 * 15%
0.25y + 12 - 0.1y = 18
0.15y = 6
y = 6 / 0.15
y = 40
Answer:
0.001145
Step-by-step explanation:
Given that you are certain to get 3 jacks when selecting 51 cards from a shuffled deck.
When we draw 3 cards from 51 cards, we keep one card aside
The card can be either Jack or non Jack
Prob (the left over card to be Jack) = P(A) = 
Prob (the left over card to be non jack ) = P(B) = 
A and B are mutually exclusive and exhaustive
Let drawing 3 Jacks be the event C
P(C) = P(AC)+P(BC)
P(BC) = P(B)*P(C/B)\\
= \frac{28}{52} (4/51C3)\\
=1.034(10^{-4}
Adding we get
P(C)
= 
