Ask question

Ask question

All categories

3 years ago

15

Using the numbers 1,2,3,4,5,6,7,8,9 use four to make it equal 19 you may only use these numbers once! Thank you! Example: 5+3+7+

4= 19

2 answers:

daser333 [38]3 years ago

8 0

8+1+7+3=19 That is one option

irga5000 [103]3 years ago

6 0

9+1+4+5=19
9+2+3+5=19
8+4+2+5=19

Here you go

You might be interested in

The regression equation below relates the scores students in an advanced statistics course received for homework completed and f

serg [7]

Answer: d.) None of the answer choices is correct

Step-by-step explanation:

The homework score is an independent variable (known) and on the x-axis, while the midterm exam is the dependent variable, so it's on the y-axis

y = 0.91x - 94.4; and x=420

Substitute x as 420 into the equation.

y = 382.2 - 94.4 = 287.8, or approximately 288.

And this value isn't in the options above.

7 0

3 years ago

Write the following decimal number in its equivalent fraction form. Show all work for full credit. 0.225

zalisa [80]

Rewrite the decimal number as a fraction with 1 in the denominator

0.225=0.22510.225=0.2251

Multiplying by 1 to eliminate 3 decimal places, we multiply top and bottom by 103 = 1000

0.2251×10001000=2251000

7 0

3 years ago

Read 2 more answers

Which of the following integers is less than -23?<br> a) o<br> b) -13<br> c) 13<br> d) -25

blondinia [14]

Answer:

i think d) -25 is answer

Step-by-step explanation:

good luck

7 0

2 years ago

Read 2 more answers

In the diagram below, assume that all points are given in rectangular coordinates. Determine the polar coordinates for each poin

Korolek [52]

Step-by-step explanation:

We have cartisean points. We are trying to find polar points.

We can find r by applying the pythagorean theorem to the x value and y values.

$r {}^{2} = {x}^{2} + {y}^{2}$

And to find theta, notice how a right triangle is created if we draw the base(the x value) and the height(y value). We also just found our r( hypotenuse) so ignore that. We know the opposite side and the adjacent side originally. so we can use the tangent function.

$\tan(x) = \frac{y}{x}$

Remeber since we are trying to find the angle measure, use inverse tan function

$\tan {}^{ - 1} ( \frac{y}{x} ) =$

Answers For 2,5

${2}^{2} + {5}^{2} = \sqrt{29} = 5.4$

So r=sqr root of 29

$\tan {}^{ - 1} ( \frac{5}{2} ) = 68$

So the answer is (sqr root of 29,68).

For -3,3

${ -3 }^{2} + {3}^{2} = \sqrt{18} = 3 \sqrt{2}$

$\tan {}^{ - 1} ( \frac{3}{ - 3} ) = - 45$

Use the identity

$\tan(x) = \tan(x + \pi)$

So that means

$\tan(x) = 135$

So our points are

(3 times sqr root of 2, 135)

For 5,-3.5

${5}^{2} + {3.5}^{2} = \sqrt{37.25}$

$\tan {}^{ - 1} ( \frac{ - 3.5}{ - 5} ) = 35$

So our points are (sqr root of 37.25, 35)

For (0,-5.4)

${0}^{2} + { - 5.4}^{2} = \sqrt{} 29.16 = 5.4$

So r=5.4

$\tan {}^{ - 1} (0) = undefined$

So our points are (5.4, undefined)

4 0

3 years ago

A batch of 580 containers for frozen orange juice contains 8 that are defective. Two are selected, at random, without replacemen

serious [3.7K]

Answer:

a. 0.12109

b. 0.0001668

c .0.9726

d. 0.01038

e. 0.01211

f. 0.000001731

Step-by-step explanation:

Sample size = 580

Defective units = 8

Number of picks = 2

a) If the first container is defective, there 7 defective containers left in a population of 579. The probability of selecting a defective one is:

$P=\frac{7}{579}=0.121$

b) The probability that both are defective is given by:

$P=\frac{8}{580}*\frac{7}{579}= 0.000167$

c) The probability that both are acceptable is given by:

$P=\frac{580-8}{580}*\frac{579-8}{579}= 0.9726$

d) In this case, two defective units were removed from the batch, the probability that the third is also defective is:

$P=\frac{6}{578}}= 0.0104$

e) In this case, one acceptable and one defective unit were removed from the batch, the probability that the third is also defective is:

$P=\frac{7}{578}= 0.01211$

f) The probability that all three are defective is given by:

$P=\frac{8}{580}*\frac{7}{579}*\frac{6}{578} = 0.000001731$

7 0

3 years ago