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Zarrin [17]
2 years ago
13

Help please i need this done!!

Mathematics
1 answer:
Juliette [100K]2 years ago
8 0

Answer:

True, True, True, False

Step-by-step explanation:

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Write<br> 9,639<br> as a decimal number.<br> 10,000
Lyrx [107]

Answer:

.9639

9.639 * 10^3

Step-by-step explanation:

This question was unclear but this is the closest I understood of.

Hope this helped! :)

4 0
3 years ago
Select steps that could be used to solve the equation 1 + 3x = -x + 4. Select all that apply
madreJ [45]
The answer for this is D.
8 0
3 years ago
Read 2 more answers
PLEASE HELP!! URGENT!! WILL GIVE BRAINLIEST TO FASTEST ANSWER!! TAKING TEST ON EDGE 2020!!
Leto [7]

Answer:

expressions which represent exponential decay:

A. 900(0.05)^t

B. 700(0.9)^x

Step-by-step explanation:

Exponential decay functions has the next form:

y = ab^x

where b < 1

A. 900(0.05)^t , a = 900, b = 0.05, the variable is t instead of x. 0.05 < 1, then it represents exponential decay

B. 700(0.9)^x , a = 700, b = 0.9 < 1, then it represents exponential decay

C. 53(1.75)^(0.3x) =  53(1.75)^(0.3)(1.75)^x, a =  53(1.75)^(0.3), b = 1.75 > 1, then it doesn't represent exponential decay

D. 90(1.2)^t, a = 90, b = 1.2 > 1,  then it doesn't represent exponential decay. (the variable is t instead of x)

E. .300(2.4)^(1.2y)  = 300(2.4)^(1.2)(2.4)^y, a = 300(2.4)^(1.2),  b = 2.4 > 1, then it doesn't represent exponential decay. (the variable is y instead of x)

F. 2x² + 9 , this is a quadratic function,  then it doesn't represent exponential decay.

G. 18 – 3y, this is a linear function,  then it doesn't represent exponential decay.

3 0
3 years ago
How is the Distributive Property used to simplify operations with scientific notation
Citrus2011 [14]

Answer:

See explanation

Step-by-step explanation:

Let a,b, and c be real numbers.

The distributive property says that:

a(b + c) = ab + ac

Assuming we want to simplify:

10(5*10^{-1}+150*10^{-3})

We apply the distributive property to get:

10(5*10^{-1}+150*10^{-3}) = 5*10^{-1} \times 10+150*10^{-3} \times 10

We can now use rules of exponents to simplify further:

10(5*10^{-1}+150*10^{-3}) = 5*10^{-1} \times 10^{1} +150*10^{-3} \times 10^{1}

10(5*10^{-1}+150*10^{-3}) = 5*10^{-1 + 1} +150*10^{-3 + 1}

10(5*10^{-1}+150*10^{-3}) = 5*10^{0} +150*10^{-2}

10(5*10^{-1}+150*10^{-3}) = 5*1+1.50*10^{-2}x {10}^{2}

10(5*10^{-1}+150*10^{-3}) = 5*1+1.50*10^{-2 + 2}

10(5*10^{-1}+150*10^{-3}) = 5+1.50*10^{0} = 6.5 \times  {10}^{0}

4 0
3 years ago
Solve for b Pythagorean
Vaselesa [24]

The figure shows a right triangle at each corner with legs 3 and b and hypotenuse 4. The Pythagorean theorem tells you the sum of the squares of the legs is equal to the square of the hypotenuse:

3² + b² = 4² . . . . . . put the numbers into the Pythagorean formula

9 + b² = 16 . . . . . . . evaluate the squares

b² = 16 - 9 = 7 . . . . subtract 9 to isolate the variable

b = √7 . . . . . . . . . . undo the square operation by taking the square root

7 0
3 years ago
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