To find the relative frequency, divide the frequency by the total number of data values. To find the cumulative relative frequency, add all of the previous relative frequencies to the relative frequency for the current row.
Answer:
The probability that a container will be shipped even though it contains 2 defectives if the sample size is 88, will be 
Step-by-step explanation:
The first step is to count the number of total possible random sets of taking a sample size of 88 engines over 1212 engines of the population, so ![\left[\begin{array}{ccc}1212\\88\end{array}\right] =1212C88=4.7205x10^{135}](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1212%5C%5C88%5Cend%7Barray%7D%5Cright%5D%20%3D1212C88%3D4.7205x10%5E%7B135%7D)
The second step is to count the number of total possible random sets of taking a sample size of 88 engines over 1210 engines (discounting the 2 defective engines) as the possible ways to succeed, so ![\left[\begin{array}{ccc}1210\\88\end{array}\right] =1212C88=4.0596x10^{135}](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1210%5C%5C88%5Cend%7Barray%7D%5Cright%5D%20%3D1212C88%3D4.0596x10%5E%7B135%7D)
Finally we need to compute
, therefore the probability that a container will be shipped is
Answer:
When an expression can be viewed as the difference of two perfect squares, i.e. a²-b², then we can factor it as (a+b)(a-b). For example, x²-25 can be factored as (x+5)(x-5). This method is based on the pattern (a+b)(a-b)=a²-b², which can be verified by expanding the parentheses in (a+b)(a-b).
Step-by-step explanation:
lol it’s on wassa name ;) mark me brainliest? Btw
Here you go, your equation should look a lot like this:
x²-16 -----> (x+4)(x-4).
Answer:
Here is the complete question (attachment).
The function which represent the given points are 
Step-by-step explanation:
We know that a general exponential function is like,
We can find the answer by hit and trial method by plugging the values of
coordinates.
Here we are going to solve this with the above general formula.
So as the points are
then for 
Can be arranged in terms of the general equation.
...equation(1) and
...equation(2)

Plugging the values in equation 2.
We have
![\frac{16}{b} b^4=128,16\times b^3=128,b=\sqrt[3]{\frac{128}{16}} =\sqrt[3]{8}=2](https://tex.z-dn.net/?f=%5Cfrac%7B16%7D%7Bb%7D%20b%5E4%3D128%2C16%5Ctimes%20b%5E3%3D128%2Cb%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B128%7D%7B16%7D%7D%20%3D%5Csqrt%5B3%5D%7B8%7D%3D2)
Plugging
in equation 1.
We have 
Comparing with the general equation of exponential
and 
So the function which depicts the above points =
From theoption we have B as the correct answer.
Answer:
Step-by-step explanation:
Given
length of three sides are
according to Euclidean geometry



also



therefore value of 
If x is an integer then x can be 