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arlik [135]
2 years ago
11

Please help me with this question it’s been stressful

Mathematics
1 answer:
vazorg [7]2 years ago
3 0

Answer:

Im not sure what it is to do but the answer i got was -886.6

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What is the equation of the line whose graph is parallel to the graph of y=3x-10
TEA [102]
Hello,

y=3x+b is parallele to y=3x-10
In order to determine b, we must know something else.

3 0
3 years ago
Solve the following equation for <br><br><br> G:2 (g-h) = b+4
Klio2033 [76]

If the equation 2(g - h) = b + 4 is solved for g. Then the value of g will be b/2 + h + 2.

<h3>What is the solution of the equation?</h3>

A combination of equations solution is a collection of values x, y, z, etc. that enable all of the calculations to true at the same time.

The equation is given below.

2(g - h) = b + 4

Then solve the equation for the value of g. Then we have

2(g - h) = b + 4

   g - h = b/2 + 2

        g = h + b/2 + 2

More about the solution of the equation link is given below.

brainly.com/question/545403

#SPJ1

3 0
2 years ago
Find the total surface area of this cone.<br> leave your answer in terms of pi<br> R=3<br> L=4
Yuliya22 [10]

Answer:

total surface area of cone is πr (r+l)

22/7 x 3 (3+4)

22/7*3 (7)

22 x 3 ( as 7 that was divided by 22 was cut out with 7 in the bracket)

hence,

TSA of cone = 66pi

8 0
2 years ago
Show another way to write 100 more than 623 ​
____ [38]
There are many ways, but here is one:

x = 100

Since ‘x’ is 100 and we want 100 more, we just need to add ‘x’ to 623

Answer: x + 623 (Make sure you define your ‘x’ value)
4 0
3 years ago
Sin tita= 0.6892.find the value Of tita correct to two decimal places<br><br>​
Anvisha [2.4K]

Answer:

\theta \approx 6.28n + 2.38,  \quad  n \in \mathbb{Z}

or

\theta \approx 6.28n + 0.76, \quad n \in \mathbb{Z}

Considering \theta \in (0, 2\pi]

\theta \approx 2.38

or

\theta \approx 0.76

Step-by-step explanation:

\sin(\theta)=0.6892

We have:

\sin (x)=a \Longrightarrow x=\arcsin (a)+2\pi n \text{ or } x=\pi -\arcsin (a)+2\pi n \text{ as } n\in \mathbb{Z}

Therefore,

\theta= \arcsin (0.6892)+2\pi n, \quad n \in \mathbb{Z}

or

\theta = \pi -\arcsin (0.6892)+2\pi n, \quad  n\in \mathbb{Z}

---------------------------------

\theta \approx 6.28n + 2.38,  \quad  n \in \mathbb{Z}

or

\theta \approx 6.28n + 0.76, \quad n \in \mathbb{Z}

4 0
3 years ago
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