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finlep [7]
3 years ago
5

Factorise fully 18e^2f^3-12e^2f

Mathematics
1 answer:
Alexeev081 [22]3 years ago
8 0

Answer:

18e^2f^3-12e^2f = 6e^2f(3f^2-2)

Step-by-step explanation:

Given

18e^2f^3-12e^2f

Required

Factorize:

18e^2f^3-12e^2f

Express 18 as 6 * 3 and 12 as 6 * 2

18e^2f^3-12e^2f = 6*3e^2f^3-6*2e^2f

Factor out 6

18e^2f^3-12e^2f = 6(3e^2f^3-2e^2f)

Factor out e^2

18e^2f^3-12e^2f = 6e^2(3f^3-2f)

Factor out f

18e^2f^3-12e^2f = 6e^2f(3f^2-2)

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Describe the pattern below then find the next two numbers 547 54.7 5.47 0.547
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Resuelve el siguiente sistemas de ecuaciones por el método
marishachu [46]

Answer:

x=10 and y=12

Step-by-step explanation:

To solve this quadratic equation we will use two method

1. Elimination method

2. substitution method

first of we use elimination method

we either eliminate x or y

we will be eliminating y

83x-20y=590..........(eq1)

60x+18y=816...........(eq2)

y will be eliminated by multiplying

(eq1) by 9

(eq2) by 10

which will give

747x-180y=5310.........(eq3)

600x-180y=8160.........(eq4)

see that y has the same value that is (-180y and +180y)

so to eliminate y completely you have to add eq1 and eq2 because if you don't add them together you wont eliminate y

747x-180y=5310

+

600x+180y=8160

=

1347x+0=13470

1347x=13470

x=13470/1347

x=10

Now to find y we use substitution method ie put x=10 in any of the equation above(eq1,eq2,eq3, eq4) you will get the same answer

eq1

83x-20y=590..... where (x=10)

83(10)-20y =590

830-20y=590

like terms

-20y=590-830

-20y= -240

divide both sides with -20

y= -240/-20

y=12

OR

eq2

60x+18y=816..... where x=10

60(10)+18y=816

600+18y=816

like term

18y=816-600

18y=216

y=216/18

y= 12

or eq3 or eq4 you will still get the same answer......

7 0
3 years ago
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