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3 years ago

Rectangle CDEF undergoes a dilation centered at the origin. The result is rectangle C'D'E'F'. Which rule describes the dilation?

Mathematics

2 answers:

lyudmila [28]3 years ago

6 0

Answer:

(x, y) → ( 1/2x,1/2y)

LiRa [457]3 years ago

3 0

Answer:

D)(x,y) → ( 1/2x, 1/2y)

Step-by-step explanation:

FE goes from x = -8 to x = 10. This makes the length of FE 18.

ED goes from y = 2 to y = -8. This makes the length of ED 10.

F'E' goes from x = -4 to x = 5. This makes the length of F'E' 9.

E'D' goes from y = 1 to y = -4. This makes the length of E'D' 5.

Comparing FE to F'E', we see that F'E' is half the length of FE.

Comparing ED to E'D', we see that E'D' is half the length of ED.

This means the dilation has a scale factor of 1/2; this means the rule is (x,y) → ( 1/2x, 1/2y)

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4 years ago

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Mamont248 [21]

T= # of rental hours
Reservation Fee= $31
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Multiply number of hours rented by the cost per hour, add that total to the reservation fee. The total needs to be less than $97.60.

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3 years ago

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3 years ago

1) Beth invests $7,417 in a savings account

Alex_Xolod [135]

Answer:

D) $11,499.63

Step-by-step explanation:

Lets use the compound interest formula provided to solve this:

$A=P(1+\frac{r}{n} )^{nt}$

P = initial balance

r = interest rate (decimal)

n = number of times compounded annually

t = time

First, change 4% into a decimal:

4% -> $\frac{4}{100}$ -> 0.04

Since the interest is compounded 6 times a year, we will use 6 for n. Lets plug in the values now:

$A=7,417(1+\frac{0.04}{6})^{6(11)}$

$A=11,499.63$

Your answer is D) $11,499.63

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3 years ago

A person must score in the upper 7% of the population on an admissions test to qualify for membership in society catering to hig

olya-2409 [2.1K]

Answer:

The minimum score a person must have to qualify for the society is 162.05

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

Test scores are normally distributed with a mean of 140 and a standard deviation of 15. This means that $\mu = 140, \sigma = 15$ .