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Basile [38]
3 years ago
10

P=I squared R solve for I

Mathematics
1 answer:
jeka943 years ago
5 0

l^2R=P\ \ \ \ |:R\neq0\\\\l^2=\dfrac{P}{R}\to l=\pm\sqrt{\dfrac{P}{R}}

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Dmitriy789 [7]

Answer:

Domain is all values of X or (-∞,∞)

Range is all the possible values of Y. Since it goes up to 3, and then it goes down, it's all values less than or equal to y, or (-∞,3] or y ≤ 3 (depending on how you need to enter the response.

Step-by-step explanation:

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3 years ago
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Answer:

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Step-by-step explanation:

2x²+ bx + 5=0 has no real solutions

=> D< 0

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