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3 years ago

Factor out the common factor. 2x4 + 5x3 – 8x –20 (x3 + 4)(–2x – 5) (x3 – 4)(2x + 5) (x3 + 4)(2x + 5)

Mathematics

2 answers:

Brums [2.3K]3 years ago

7 0

Answer:

$(x^3-4)(2x+5)$

Step-by-step explanation:

$2x^4 + 5x^3 - 8x -20$

To factor this we use grouping method

$(2x^4 + 5x^3)+(- 8x -20)$

Take out GCF from each group. x^3 is the GCF for first group and -4 is the GCF from second group

$x^3(2x+5)-4(2x+5)$

Now we factor out 2x+5

$(x^3-4)(2x+5)$

horsena [70]3 years ago

4 0

Answer:

The common factor is (x3 – 4)(2x + 5)

Step-by-step explanation:

1. find gcf

2. factor out the gcf

3. use grouping

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Choose the graph below that represents the following system of inequalities:

castortr0y [4]

Yshejrhhe is they easiest of them all and as you can see I just can’t fail it bro ik too smart yk it’s y>-3x +1-5

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2 years ago

Sarah would like to make a 6 lb nut mixture that is 60% peanuts and 40% almonds. She has several pounds of a mixture that is 80%

weeeeeb [17]

Answer: a. The system that models this situation is,

x + y = 6 , 8 x + 5 y = 36.

b. Solution is x = 2lb and y = 4lb

where x is the quantity of 80% of peanuts mixture mix with y quantity of 50% of peanuts mixture for making 60% of peanuts mixture.

Step-by-step explanation:

Let x quantity of 80% of peanuts mixture mix with y quantity of 50% of peanuts mixture for making 60% of peanuts mixture.

Then According to the question,

x + y = 6 --------- (1)

And, 80 % of x + 50 % of y = 60 % of 6

⇒ 0.8 x + 0.5 y = 3.6

⇒ 8 x + 5 y = 36 --------- (2)

Where equation 1) and equation 2) are the required equation which models the given situation.

Now, 8 × equation 1)

We get, 8 x + 8 y = 48 ----------(3)

equation (3) - equation (2)

we get, 3 y = 12

⇒ y = 4

By putting the value of y in equation (2)

we get, x = 2

Thus, he mixed 2 lb of mixture 80/20 and 4 lb of mixture 50/50 for making 6 lb of 50/50 mixture.

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3 years ago

Is the given point interior , exterior, or on the circle k (x+2)2 + (y-3)2 =18 P (8,4)

Mnenie [13.5K]

One way would be to find the distance from the point to the center of the circle and compare it to the radius

for
$(x-h)^2+(y-k)^2=r^2$
the center is (h,k) and the radius is r

and the distance formula is
distance between $(x_1,y_1)$ and $(x_2,y_2)$ is
$D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$

r=radius
D=distance form (8,4) to center

if r>D, then (8,4) is inside the circle
if r=D, then (8,4) is on the circle
if r<D, then (8,4) is outside the circle

so
$(x+2)^2+(y-3)^2=18$
$(x-(-2))^2+(y-3)^2=(\sqrt{18})^2$
$(x-(-2))^2+(y-3)^2=(3\sqrt{2})^2$

the radius is $3\sqrt{2}$
center is (-2,3)

find distance between (8,4) and (-2,3)

$D=\sqrt{(8-(-2))^2+(4-3)^2}$
$D=\sqrt{(8+2)^2+(1)^2}$
$D=\sqrt{10^2+1}$
$D=\sqrt{100+1}$
$D=\sqrt{101}$

$r=3\sqrt{2}$ ≈4.2
$D=\sqrt{101}$ ≈10.04

do r<D

(8,4) is outside the circle

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3 years ago

A rain gauge had 0.6 centimeter of rain after 2 hours, 0.9 centimeter after 3 hours, 1.2 centimeters after 4 hours, and 1.5 cent

Ulleksa [173]

Answer: 0.3 cm per hour

Step-by-step explanation:

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gulaghasi [49]

Answer:

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Step-by-step explanation:

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3 years ago