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kkurt [141]
3 years ago
11

9) work out 6 - 3x-2--10​

Mathematics
1 answer:
Kaylis [27]3 years ago
3 0
3x+6 I believe because you can’t add a number with a variable to a number without one
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Solving simultaneous equations with one quadratic, x^2+y^2=16 and y=x+3
Svetlanka [38]
If y=x+3, then in the first equation you have

x^2+(x+3)^2=x^2+(x^2+6x+9)=2x^2+6x+9=16

Rewriting a bit, you get

x^2+3x+\dfrac92=8

x^2+3x+\dfrac94+\dfrac94=8

\left(x+\dfrac32\right)^2=\dfrac{23}4

x=-\dfrac32\pm\dfrac{\sqrt{23}}2

Now, since y=x+3, you also get

y=-\dfrac32\pm\dfrac{\sqrt{23}}2+3=\dfrac32\pm\dfrac{\sqrt{23}}2

So, there are two solutions here:

(x,y)=\left(-\dfrac32+\dfrac{\sqrt{23}}2,\dfrac32+\dfrac{\sqrt{23}}2\right)
(x,y)=\left(-\dfrac32-\dfrac{\sqrt{23}}2,\dfrac32-\dfrac{\sqrt{23}}2\right)
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Step-by-step explanation:

1,203.44-300=903.44

903.44-60=843.44

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Step-by-step explanation:

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How do you create a equivalent expression to 12n -6x+48
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Answer:

Step-by-step explanation:

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