I am big pp lol xD hxyjdrh
horizontal shift: 3 units to the left
vertical shift: 4 units down
ok thats cool ig what do you need help with
K+3 3/4=5 2/3-1 1/3
k+3 3/4=4 1/3
lets find the lcm first then multiply both sides by it but first change it to improper fraction
LCM is 12
[k+15/4]=[13/3]12
12k+45=52
12k=7
k=7/12
3/2 We look for a number that goes into both 9 and 6 without leaving a remainder, and that number is 3
