Answer:
Ix = Iy =
Radius of gyration x = y =
Step-by-step explanation:
Given: A lamina with constant density ρ(x, y) = ρ occupies the given region x2 + y2 ≤ a2 in the first quadrant.
Mass of disk = ρπR2
Moment of inertia about its perpendicular axis is . Moment of inertia of quarter disk about its perpendicular is .
Now using perpendicular axis theorem, Ix = Iy = = .
For Radius of gyration K, equate MK2 = MR2/16, K= R/4.
decreases
quadrilaterals:))))))))))))
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This is the right answer
Answer: %0.25
Do 1 divided by 4