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matrenka [14]
3 years ago
8

Help?? um i can’t select multiple pics so..the other two Drop down menus say ..

Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
3 0

Answer:

Step-by-step explanation:

\frac{x^2 -3x-10}{x^2 -6x+5} × \frac{x-2}{x-5} = \frac{(x-5)(x+2)}{(x-5)(x-1)} × \frac{x-2}{x-5} = \frac{(x+2)(x-2)}{(x-1)(x-5)}  ( Domain is x ≠ 1 and x ≠ 5 )

The expression has an excluded value of x = 5

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A bag contain 5 red marbles,4 green marbles and 1 blue marble. A marble is chosen at random from the bag and not replaced; then
jarptica [38.1K]

Answer:

\frac{2}{15}

Step-by-step explanation:

GIVEN: A bag contain 5 red marbles,4 green marbles and 1 blue marble. A marble is chosen at random from the bag and not replaced, then a second marble is chose.

TO FIND: What is the probability both marbles are green.

SOLUTION:

Total marbles in bag =10

total number of green marbles =4

Probability that first marble will be green P(A)=\frac{\text{total green marbles}}{\text{total marbles}}

                                                                    =\frac{4}{10}=\frac{2}{5}

Probability that second marble will be green P(B)=\frac{\text{total green marble in bag}}{\text{total marble in bag}}

                                                                                    \frac{3}{9}=\frac{1}{3}

As both events are disjoint

probability both marbles are green =P(A)\times P(B)

                                                           =\frac{2}{5}\times\frac{1}{3}=\frac{2}{15}

Hence  the probability both marbles are green is \frac{2}{15}

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3 years ago
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