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Natasha2012 [34]
3 years ago
15

Consider the problem: 1/2 ÷ 5. Which model correctly represents this expression? How do you know?

Mathematics
1 answer:
frosja888 [35]3 years ago
3 0

Answer:

\frac{1}{10}

Step-by-step explanation:

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Your students need to understand the relationships among objects on a graph. You ask students to:
tino4ka555 [31]
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6 0
2 years ago
Solve 1/11c > 9. Graph the solution. . The solution is​
Katarina [22]

Answer:

I suppose that the inequality is:

(1/11)*c > 9.

To solve this we need to isolate c in one side of the inequality.

To isolate it, we need to multiply both sides by 11, then we get:

11*(1/11)*c > 9*11

c > 9*11 = 99

c > 99.

To graph this, we will have an open dot at c = 99, and an arrow that points to the right direction.

The graph is shown below.

5 0
3 years ago
catering service offers 8 ​appetizers, 11 main​ courses, and 7 desserts. A banquet committee is to select 7 ​appetizers, 8 main​
guapka [62]

Answer:  The required number of ways is 46200.

Step-by-step explanation:  Given that a catering service offers 8 ​appetizers, 11 main​ courses, and 7 desserts.

A banquet committee is to select 7 ​appetizers, 8 main​ courses, and 4 desserts.

We are to find the number of ways in which this can be done.

We know that

From n different things, we can choose r things at a time in ^nC_r ways.

So,

the number of ways in which 7 appetizers can be chosen from 8 appetizers is

n_1=^8C_7=\dfrac{8!}{7!(8-7)!}=\dfrac{8\times7!}{7!\times1}=8,

the number of ways in which 8 main courses can be chosen from 11 main courses is

n_2=^{11}C_8=\dfrac{11!}{8!(11-8)!}=\dfrac{11\times10\times9\times8!}{8!\times3\times2\times1}=165

and the number of ways in which 4 desserts can be chosen from 7 desserts is

n_3=^7C_4=\dfrac{7!}{4!(7-4)!}=\dfrac{7\times6\times5\times4!}{4!\times3\times2\times1}=35.

Therefore, the number of ways in which the banquet committee is to select 7 ​appetizers, 8 main​ courses, and 4 desserts is given by

n=n_1\times n_2\times n_3=8\times165\times35=46200.

Thus, the required number of ways is 46200.

7 0
4 years ago
- b. Yolanda played a new number game with Xavier. She used this equation to generate her response to each number Xavier said: y
Arisa [49]

(a) One possibility is 8.45

Rounded to the nearest integer = 8

Rounded to the nearest tenth = 8.5

And rounding this to the nearest integer = 9

 

(b) The possible numbers are 8.45 to 8.49, inclusively

3 0
3 years ago
Read 2 more answers
Help PLZ <br> plz tell me which should i choose.
Alex_Xolod [135]

Answer:

4

Step-by-step explanation:

If Log a×=16diameter then value of log =4

3 0
3 years ago
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