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3 years ago

Can somebody help me answer this question and show how you got to answer please

Mathematics

2 answers:

Diano4ka-milaya [45]3 years ago

4 0

29.35 miles together. You just add each of their miles and get their miles together as a total.

Aleks04 [339]3 years ago

4 0

It's 29.35 together. I think. Hope helped

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If Jordan had his hourly salary increase from $9.25 per hour to $10.75 per hour, which of the following is

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Jordan’s salary increased by about 16.2%

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3 years ago

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For what values of $x$ is $$\frac{x^2 + x + 3}{2x^2 + x - 6} \ge 0?$$ note: be thorough and explain why all points in your answe

Rus_ich [418]

To solve the inequality $\frac{x^2+x+3}{2x^2+x-6}\ge \:0$

$\mathrm{Factor\:the\:left\:hand\:side\:}\frac{x^2+x+3}{2x^2+x-6}:$

The numerator $x^2+x+3$ is not factorizable.

so factor the denominator $2x^2+x-6$ :

$2x^2+x-6=\left(2x^2-3x\right)+\left(4x-6\right)=x\left(2x-3\right)+2\left(2x-3\right)\\ \mathrm{Factor\:out\:}x\mathrm{\:from\:}2x^2-3x\mathrm{:\quad }x\left(2x-3\right)\\ \mathrm{Factor\:out\:}2\mathrm{\:from\:}4x-6\mathrm{:\quad }2\left(2x-3\right)\\$

Now take $\mathrm{Factor\:out\:common\:term\:}\left(2x-3\right)$

Then we get factor of the denominator as $\left(2x-3\right)\left(x+2\right)$

Thus $\frac{x^2+x+3}{2x^2+x-6}=\frac{x^2+x+3}{\left(x+2\right)\left(2x-3\right)}$

Now $\mathrm{Compute\:the\:signs\:of\:the\:factors\:of\:}\frac{x^2+x+3}{\left(x+2\right)\left(2x-3\right)}\\$

Signs of $x^2+x+3>0$

$\mathrm{Choosing\:ranges\:that\:satisfy\:the\:required\:condition:}\:\ge \:\:0$

$x\frac{3}{2}$ is the required solution of the given inequality.

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4 years ago

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What value of z makes the equation true? 5/6=z/12 A. 6 B. 10 C. 15 D. 5

vazorg [7]

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3 years ago

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vagabundo [1.1K]

Step-by-step explanation:

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2 years ago

You are studying the relationship between the history of early childhood trauma (categorized as trauma/no trauma) and weight in

jeka57 [31]

Answer:

You can decide to reject the Null Hypothesis at p < 0.05.

Step-by-step explanation:

In this case, the relationship between the history of early childhood trauma and weight in adulthood are being studied.

The categories of childhood trauma are:

Trauma and No trauma.

So, number of rows is, r = 2.

The categories of weight in adulthood are:

Low to normal, Overweight, and Obese

So, number of columns is, c = 3.

The distribution of the statistic $\chi^{2}$ is chi-square with (r - 1)(c - 1) degrees of freedom, where r represents the number of rows in the two-way table and c represents the number of columns.

Compute the degrees of freedom as follows:

$df = (r-1)(c-1)=(2-1) \times (3-1) = 2$

It is provided that the calculated value of Chi-square test statistic is 18.26.

Compute the p-value of the test as follows:

$p-value=P(\chi^{2}_{2}\geq 18.26)\\=0.000108\\\approx0.00011$

Decision rule:

The null hypothesis will be rejected if the p-value of the test is less than the significance level.

The significance level is, α = 0.05.

p-value = 0.00011 < α = 0.05.

The null hypothesis will be rejected at 5% level of significance.

Thus, the complete statement is:

"You can decide to reject the Null Hypothesis at p < 0.05."

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3 years ago