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3 years ago

WILL GIVE BRAINLIEST

Mathematics

2 answers:

andreyandreev [35.5K]3 years ago

7 0

Answer:

<h2>Original: M(3.5, 2) L(5.5, 2) K(7,5) J(2,5).</h2><h2>Reflected: M(3.5, -2) L(5.5, -2) K(7,-5) J(2,-5).</h2>

Step-by-step explanation:

The coordinates of the given trapezoid JKLM are

M(3.5, 2) L(5.5, 2) K(7,5) J(2,5).

If we want to reflect the trapezoid JKLM over the x-axis, we just need to change its vertical coordinates for their opposite, that is

M(3.5, -2) L(5.5, -2) K(7,-5) J(2,-5).

There reason of this is because if we need a reflection across x-axis, what changes is vertical coordintes, because the figure must go from I quadrant to IV quadrant where y-valus are negative, and x-values remains positive.

Therefore, the ordered pair of the original figure are:

M(3.5, 2) L(5.5, 2) K(7,5) J(2,5).

The ordered pair of the reflection are:

M(3.5, -2) L(5.5, -2) K(7,-5) J(2,-5).

jok3333 [9.3K]3 years ago

3 0

Answer:

J'(-2,5)

K'(-7,5)

M'(-3.5,2)

L'(5.5,2)

Step-by-step explanation:

Please refer to the image attached to this answer.

Trapezoid JKLM is reflected over the x-axis, what do we notice about the ordered pairs of the original figure and the ordered pairs of its reflection over the x-axis is described below.

Point J , K L and M , when reflected over x axis , there distance from the y axis remains the same in second quadrant. the x coordinate becomes negative however the y coordinates remains the same.

The coordinates will be as shown in the image attached.

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