Answer:
or x+3/x
Step-by-step explanation:
Using D.O.T.S (difference of two squares) formula :
Factorise the second bit:
Now write out this fraction:
Now we can cancel out repeated terms (x-3):
This is our final answer:
Answer:
y= 30°
Step-by-step explanation:
y° +y°+y°+y°+y°+y°=180°
6y°=180°
y=30°
Answer:
If the equation's roots are 1 , 3, 3 then the equation can be formed by multiplying
(x -1) * ( x - 3) * (x-3) =0
x^2 -6x + 9 * (x -1) equals
x^3 -6x^2 +9x -x^2 + 6x -9 = 0 equals
x^3 -7x^2 + 15x -9 = 0
cubic equations GENERALLY have the form
ax^3 +bx^2 + cx +d = 0
Therefore
a =1 b = -7 c = 15 and d = -9
So, to make the numbers equal the equation in the problem:
x^3 + ax^2 + bx + c = 0
a = -7 b = 15 and c = -9
Step-by-step explanation:
In electromagnetism, absolute permittivity, often simply called permittivity, usually denoted by the Greek letter ε (epsilon), is the measure of capacitance that is encountered when forming an electric field in a particular medium. More specifically, permittivity describes the amount of charge needed to generate one unit of electric flux in a given medium. A charge will yield more electric flux in a medium with low permittivity than in a medium with high permittivity. Permittivity is the measure of a material's ability to store an electric field in the polarization of the medium.
▪️The SI unit for permittivity is farad per meter (F/m or F·m−1).
The lowest possible permittivity is that of a vacuum.[citation needed] Vacuum permittivity, sometimes called the electric constant, is represented by ε0 and has a value of approximately 8.85×10−12 F⋅m−1.
The permittivity of a dielectric medium is often represented by the ratio of its absolute permittivity to the electric constant. This dimensionless quantity is called the medium's relative permittivity, sometimes also called "permittivity". Relative permittivity is also commonly referred to as the dielectric constant, a term which has been deprecated in physics and engineering[1] as well as in chemistry.[2]
By definition, a perfect vacuum has a relative permittivity of exactly 1. The difference in permittivity between a vacuum and air can often be considered negligible, as κair = 1.0006.
Relative permittivity is directly related to electric susceptibility (χ), which is a measure of how easily a dielectric polarizes in response to an electric field.
