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2 years ago

HELPPPPPPPP NOWWWW! WILL MARK BRAINLIESTTTTT!

Mathematics

1 answer:

OLEGan [10]2 years ago

5 0

1. slope of the given line = 1/5
the equation is
(y-2)/(x-(-2))=1/5
x+2=5y-10
x-5y+12=0

2. slope of the given line = -1/6
the equation is
(y-9)/x=6
y-9=6x
y=6x+9

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Find all the powers of 4 in the range 4-1000

lara31 [8.8K]

4¹ = 4
4² = 16
4³ = 64
4⁴ = 256

(4⁵ = 1,024 too big)

3 0

3 years ago

Simplify each expression using order of operations. (the one that’s circled)

Zepler [3.9K]

Answer:

Step-by-step explanation:

1. 6x6=36

2. 8+36=44

3. 44/11=4

4. 7x2=14

5. 4+14=18

5 0

2 years ago

What is the area of this triangle ?

oee [108]

Answer:

Area of triangle is 9.88 units^2

Step-by-step explanation:

We need to find the area of triangle

Given E(5,1), F(0,4), D(0,8)

We will use formula:

$Area\,\,of\,\,triangle =\sqrt{s(s-a)(s-b)s-c)} \\where\,\, s = \frac{a+b+c}{2}$

We need to find the lengths of side DE, EF and FD

Length of side DE = a = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Length of side DE = a = $=\sqrt{(5-0)^2+(1-8)^2}\\=\sqrt{(5)^2+(-7)^2}\\=\sqrt{25+49}\\=\sqrt{74}\\=8.60$

Length of side EF = b = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Length of side EF = b = $=\sqrt{(0-5)^2+(4-1)^2}\\=\sqrt{(-5)^2+(3)^2}\\=\sqrt{25+9}\\=\sqrt{34}\\=5.8$

Length of side FD = c = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Length of side FD = c = $=\sqrt{(0-0)^2+(8-4)^2}\\=\sqrt{(0)^2+(4)^2}\\=\sqrt{0+16}\\=\sqrt{16}\\=4$

so, a= 8.60, b= 5.8 and c = 4

s = a+b+c/2

s= 8.6+5.8+4/2

s= 9.2

Area of triangle= $=\sqrt{s(s-a)(s-b)s-c)}\\=\sqrt{9.2(9.2-8.6)(9.2-5.8)(9.2-4)}\\=\sqrt{9.2(0.6)(3.4)(5.2)}\\=\sqrt{97.5936}\\=9.88$

So, area of triangle is 9.88 units^2

4 0

3 years ago

Just need the explain your answer part. Can anyone help seventh grade math please DESPRATE

Dima020 [189]

9514 1404 393

Answer:

140, 35, 260/35, 7.43, 8

Step-by-step explanation:

The last section is just a summary of the preceding sections, a short description of the problem and how you worked it.

She sells the jackets for 140% of $25, or $35. 260/35 = 7.43 She can only sell a whole number of jackets, so she needs to sell 8.

8 0

3 years ago

Write the standard form of an equation of an ellipse subject to the given conditions.

irina [24]

Answer:

The answer is below

Step-by-step explanation:

The standard form of the equation of an ellipse with major axis on the y axis is given as:

$\frac{(x-h)^2}{b^2} +\frac{(y-k)^2}{a^2} =1$

Where (h, k) is the center of the ellipse, (h, k ± a) is the major axis, (h ± b, k) is the minor axis, (h, k ± c) is the foci and c² = a² - b²

Since the minor axis is at (37,0) and (-37,0), hence k = 0, h = 0 and b = 37

Also, the foci is at (0,5) and (0, -5), therefore c = 5

Using c² = a² - b²:

5² = a² - 37²

a² = 37² + 5² = 1369 + 25

a² = 1394

Therefore the equation of the ellipse is:

$\frac{x^2}{1369}+ \frac{y^2}{1394} =1$

6 0

2 years ago