Answer:
Let n be the number
100% of a number is 15 is written as: 100% × n = 15
100% = 100 / 100 = 1
Hence
100% × n = n = 15
We now need to find 50% of the number
50% of 15 = (50 / 100) × 15 = 750 / 100 = 7.5
Step-by-step explanation:
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Answer:
B. Stratified random sample is the correct answer
2x² - 4x - 30
2(x²) - 2(4x) - 2(15)
2(x² - 4x - 15)
Answer:
Step-by-step explanation:
By applying tangent rule in the given right triangle AOB,
tan(30°) = ![\frac{\text{Opposite side}}{\text{Adjacent side}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%7BOpposite%20side%7D%7D%7B%5Ctext%7BAdjacent%20side%7D%7D)
![\frac{1}{\sqrt{3}}=\frac{BO}{OA}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5Csqrt%7B3%7D%7D%3D%5Cfrac%7BBO%7D%7BOA%7D)
![OA=BO(\sqrt{3})](https://tex.z-dn.net/?f=OA%3DBO%28%5Csqrt%7B3%7D%29)
By applying tangent rule in the given right triangle BOC,
tan(60°) = ![\frac{OC}{BO}](https://tex.z-dn.net/?f=%5Cfrac%7BOC%7D%7BBO%7D)
OC = BO(√3)
OA + OC = AC
![BO(\sqrt{3})+BO(\sqrt{3}) =60](https://tex.z-dn.net/?f=BO%28%5Csqrt%7B3%7D%29%2BBO%28%5Csqrt%7B3%7D%29%20%3D60)
2√3(BO) = 60
BO = 10√3
OC = BO(√3)
OC = (10√3)(√3)
OC = 30
By applying tangent rule in right triangle DOC,
tan(60°) = ![\frac{OD}{OC}](https://tex.z-dn.net/?f=%5Cfrac%7BOD%7D%7BOC%7D)
OD = OC(√3)
OD = 30√3
Since, BD = BO + OD
BD = 10√3 + 30√3
BD = 40√3
≈ 69.3