The ways we can prove the triangles congruent:
SAS (side, angle, side)
ASA (angle, side, angle)
AAS (angle, angle, side)
SSS (all sides equal)
RHS/HL (Right Angle-Hypotenuse-Side/Hypotenuse-legs)
In these cases:
A. <B = <E
<A = <D
AC=DF
AAS (angle, angle, side) could be used.
B. AB=ED
BC=EF
AC=DF
SSS (all sides equal) could be used.
C.<BEA=<CED (right opposite angles)
As there is only one pair of equal angles we can find,there is not enough information.
D.<B = <E
BC=CE
<ECD < ACE(right opposite angles)
ASA (angle, side, angle) could be used.
Hope it helps!
The answer is is 24 5 +9=15+9=24
Answer:
+ 2y \le 3.\]Plot the region $\mathcal{R},$ and identify the vertices of polygon $\mathcal{R}.$ (b) Find the maximum value of $x + y$ among all points $(x,y)$ in $\mathcal
Answer:
Put 0 in the box.
Step-by-step explanation:
The value x = 0 if replaced in the given equation will always make the denominator zero.
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