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astraxan [27]
3 years ago
7

What is the value of -2/5 ÷ 3/4

Mathematics
1 answer:
ale4655 [162]3 years ago
8 0
-8/15 hope it helps!
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What transformation of the parent function f(x) is made to get 4f(x+2)
LenKa [72]

Answer: A vertical stretch of 4 and a translation of -2 units in the x-direction.

Step-by-step explanation:

       Changes of the parent function can be written, in this case as <em>a</em>f(x)(x - <em>k</em>) where <em>a</em> is the stretch factor and <em>k</em> is the movement left or right on the x-axis.

       In this case, a = 4 and k = 2. Since the k is negative, the function will be moved -2 units on the x-axis.

<em>Learn more about </em><em>transformations of a parent function</em><em> here:</em>

<em>brainly.com/question/13822715</em>

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2 years ago
Graph the linear function. f(x) = -3x + 1
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Here’s the graph. I hope this is right

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3 years ago
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Acute angle DOG with a measure of 45
IrinaVladis [17]

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angle of 45° is drawn.

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3 0
3 years ago
Let θ
konstantin123 [22]

Answer:

θ is decreasing at the rate of \frac{21}{16} units/sec

or \frac{d}{dt}(θ) = \frac{-21}{16}

Step-by-step explanation:

Given :

Length of side opposite to angle θ is y

Length of side adjacent to angle θ is x

θ is part of a right angle triangle

At this instant,

x =  8 , \frac{dx}{dt} = 7

( \frac{dx}{dt} denotes the rate of change of x with respect to time)

y = 8 , \frac{dy}{dt} = -14

( The negative sign denotes the decreasing rate of change )

Here because it is a right angle triangle,

tanθ = \frac{y}{x}-------------------------------------------------------------------1

At this instant,

tanθ = \frac{8}{8} = 1

Therefore θ = π/4

We differentiate equation (1) with respect to time in order to obtain the rate of change of θ or \frac{d}{dt}(θ)

\frac{d}{dt} (tanθ) = \frac{d}{dt} (y/x)

( Applying chain rule of differentiation for R.H.S as y*1/x)

sec^{2}θ\frac{d}{dt}(θ) = \frac{1}{x}\frac{dy}{dt} - \frac{y}{x*x}\frac{dx}{dt}-----------------------2

Substituting the values of x , y , \frac{dx}{dt} , \frac{dy}{dt} , θ at that instant in equation (2)

2\frac{d}{dt}(θ) = \frac{1}{8}*(-14)- \frac{8}{8*8}*7

\frac{d}{dt}(θ) = \frac{-21}{16}

Therefore θ is decreasing at the rate of \frac{21}{16} units/sec

or  \frac{d}{dt}(θ) = \frac{-21}{16}

3 0
3 years ago
Help please I'm confused. I'll give a brainliest
krek1111 [17]
The answer for the question is A. always 
5 0
3 years ago
Read 2 more answers
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