Answer:
C just took the test
Step-by-step explanation:
have a good rest of your day
Answer:
![\frac{dy}{dx}=-[(\frac{5x+24}{36x-6x^2})]](https://tex.z-dn.net/?f=%5Cfrac%7Bdy%7D%7Bdx%7D%3D-%5B%28%5Cfrac%7B5x%2B24%7D%7B36x-6x%5E2%7D%29%5D)
Step-by-step explanation:
Given function:
y =
we know
= ln(A) - ln(B)
thus,
y = 
or
also,
ln(Aⁿ) = n × ln(A)
thus,
y = 
therefore,
![\frac{dy}{dx}=[(\frac{3}{2})\times\frac{1}{(6-x)}\times(0 - 1)] - [ (\frac{2}{3})\times\frac{1}{x}\times1]](https://tex.z-dn.net/?f=%5Cfrac%7Bdy%7D%7Bdx%7D%3D%5B%28%5Cfrac%7B3%7D%7B2%7D%29%5Ctimes%5Cfrac%7B1%7D%7B%286-x%29%7D%5Ctimes%280%20-%201%29%5D%20-%20%5B%20%28%5Cfrac%7B2%7D%7B3%7D%29%5Ctimes%5Cfrac%7B1%7D%7Bx%7D%5Ctimes1%5D)
or

or
![\frac{dy}{dx}=-[(\frac{3(3x)+2\times2(6-x)}{2(6-x)\times(3x)})]](https://tex.z-dn.net/?f=%5Cfrac%7Bdy%7D%7Bdx%7D%3D-%5B%28%5Cfrac%7B3%283x%29%2B2%5Ctimes2%286-x%29%7D%7B2%286-x%29%5Ctimes%283x%29%7D%29%5D)
or
![\frac{dy}{dx}=-[(\frac{5x+24}{36x-6x^2})]](https://tex.z-dn.net/?f=%5Cfrac%7Bdy%7D%7Bdx%7D%3D-%5B%28%5Cfrac%7B5x%2B24%7D%7B36x-6x%5E2%7D%29%5D)
Answer:
Approximately 68%.
Step-by-step explanation:
The Empirical Rule states that, for a normally distributed random variable:
Approximately 68% of the measures are within 1 standard deviation of the mean.
Approximately 95% of the measures are within 2 standard deviations of the mean.
Approximately 99.7% of the measures are within 3 standard deviations of the mean.
In this problem, we have that:
Mean = 1, standard deviation = 0.05.
Estimate the percent of pails with volumes between 0.95 gallons and 1.05 gallons.
0.95 = 1 - 0.05
1.05 = 1 + 0.05
So within 1 standard deviation of the mean, which by the Empirical Rule, is approximately 68% of values.
the original price is "x", or 100%.
but we know that if we reduce "x" by 20%, namely 100% - 20% = 80%, the 80% of "x" is really £50, what is "x" or the 100% anyway?
