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lord [1]
2 years ago
10

Can someone help with this here’s a pic of the problem

Mathematics
1 answer:
insens350 [35]2 years ago
3 0

It's not entirely clear what the full instructions are, and I wish your teacher posted a diagram of figures A and B. However, I think I know what your teacher is after.

I'm assuming this is pertaining to similar polygons.

The larger figure has a side length of 88 ft and corresponds to the smaller side length of 11 ft. This is a scale factor of 11/88 = 1/8 = 0.125

What it means is that we multiply each larger side length by 1/8 or 0.125 to get the smaller corresponding side length. In other words, 88*(1/8) = 11

Square this linear scale factor to get the area scale factor

(1/8)^2 = (0.125)^2 = 0.015625

This value of 0.015625 is the area scale factor. We multiply this by the area of figure A to get

4928*0.015625 = 77

This is how your teacher got 77 as the final answer for figure B.

------------------------------------------------------

Admittedly this concept is a bit confusing at first.

Let's do another example.

Consider a 2 by 3 rectangle of area 2*3 = 6 square units.

Now apply a linear scale factor of 4 to quadruple each side. We get a 8 by 12 rectangle of area 8*12 = 96.

Notice the jump from 6 to 96 is "times 16" (since 96/6 = 16) and it's no coincidence that 16 is 4^2, i.e. the result of squaring the linear scale factor.

new area = (area scale factor)*(old area)

new area = 16*(old area)

new area = 16*6

new area = 96

This shows that 16 is the area scale factor.

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(0,5)

Step-by-step explanation:

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If < A and < B are vertical angles, and < A = 5x - 1 degrees, and < B = 4x + 4 degrees, find x.
ArbitrLikvidat [17]

Answer:

x = 5

Step-by-step explanation:

vertical angles are congruent , so

∠ A = ∠ B , that is

5x - 1 = 4x + 4 ( subtract 4x from both sides )

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2 years ago
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The correct answer is

F. x = 8

8 0
3 years ago
Mrs. Van and her family went bowling. The total cost of the shoes was $12 and the cost to bowl was $5 per game. Write an equatio
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3 years ago
Match the expressions with their equivalent simplified expressions.
Tasya [4]

Answer:

\sqrt[4]{\frac{16x^6y^4}{81x^2y^8}}\rightarrow\frac{2x}{3y}\\\sqrt[4]{\frac{81x^2y^{10}}{81x^6y^6}} \rightarrow\frac{3y}{2x}\\\sqrt[3]{\frac{64x^8y^7}{125x^2y^{10}}}\rightarrow\frac{4x^2}{5y}\\\sqrt[5]{\frac{243x^{17}y^{16}}{32x^7y^{21}}}\rightarrow\frac{3x^2}{2y}\\\sqrt[5]{\frac{32x^{12}y^{15}}{243x^7y^{10}}} \rightarrow\frac{2xy}{3}\\\sqrt[4]{\frac{16x^{10}y^{9}}{256x^2y^{17}}}\rightarrow\frac{x}{2y}


Step-by-step explanation:

\sqrt[4]{\frac{16x^6y^4}{81x^2y^8}} =\sqrt[4]{\frac{(2^4)(x^{6-2})(y^{4-8})}{(3^4)}} =\sqrt[4]{\frac{2^4x^4y^{-4}}{3^4}} =\frac{2xy^{-1}}{3}=\frac{2x}{3y}

\sqrt[4]{\frac{81x^2y^{10}}{81x^6y^6}} =\sqrt[4]{\frac{(3^4)(x^{2-6})(y^{10-6})}{(2^4)}} =\sqrt[4]{\frac{3^4x^{-4}y^{4}}{2^4}} =\frac{3x^{-1}y^1}{3}=\frac{3y}{2x}

\sqrt[3]{\frac{64x^8y^7}{125x^2y^{10}}} =\sqrt[3]{\frac{(4^3)(x^{8-2})(y^{7-10})}{(5^3)}} =\sqrt[3]{\frac{4^3x^6y^{-3}}{5^3}} =\frac{4x^2y^{-1}}{5}=\frac{4x^2}{5y}

\sqrt[5]{\frac{243x^{17}y^{16}}{32x^7y^{21}}} =\sqrt[5]{\frac{(3^5)(x^{17-7})(y^{16-21})}{(2^5)}} =\sqrt[5]{\frac{3^5x^{10}y^{-5}}{2^5}} =\frac{3x^2y^{-1}}{2}=\frac{3x^2}{2y}

\sqrt[5]{\frac{32x^{12}y^{15}}{243x^7y^{10}}} =\sqrt[5]{\frac{(2^5)(x^{12-7})(y^{15-10})}{(3^5)}} =\sqrt[5]{\frac{2^5x^{5}y^{5}}{3^5}} =\frac{2x^1y^{1}}{3}=\frac{2xy}{3}

\sqrt[4]{\frac{16x^{10}y^{9}}{256x^2y^{17}}} =\sqrt[4]{\frac{(2^4)(x^{10-2})(y^{9-17})}{(4^4)}} =\sqrt[4]{\frac{2^4x^{8}y^{-8}}{4^4}} =\frac{2x^{1}y^{-1}}{4}=\frac{x}{2y}

Thus,

\sqrt[4]{\frac{16x^6y^4}{81x^2y^8}}\rightarrow\frac{2x}{3y}\\\sqrt[4]{\frac{81x^2y^{10}}{81x^6y^6}} \rightarrow\frac{3y}{2x}\\\sqrt[3]{\frac{64x^8y^7}{125x^2y^{10}}}\rightarrow\frac{4x^2}{5y}\\\sqrt[5]{\frac{243x^{17}y^{16}}{32x^7y^{21}}}\rightarrow\frac{3x^2}{2y}\\\sqrt[5]{\frac{32x^{12}y^{15}}{243x^7y^{10}}} \rightarrow\frac{2xy}{3}\\\sqrt[4]{\frac{16x^{10}y^{9}}{256x^2y^{17}}}\rightarrow\frac{x}{2y}

3 0
4 years ago
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