Okay so to do the sqrt(75) you see if there are hidden squares. Split it to be the sqrt(25) and sqrt(3) then simplify. In the end, you get 5sqrt(3). Hope this helps!
Since one bus holds 36 students and 4 adults, 40 people are in one bus so...
40 (6)
=240
Total 240 people are going on the field trip.
Hope this helped you.
Have a great day!
The 400th term is 425.There are floor(√400) = 20 squares in the range 1..400, so the 400th term will be at least 420. There are floor(∛420) = 7 cubes in the range 1..400, so the 400th term may be as high as 427. However, there are
![\lfloor\sqrt[6]{427}\rfloor=2](https://tex.z-dn.net/?f=%5Clfloor%5Csqrt%5B6%5D%7B427%7D%5Crfloor%3D2)
numbers that are both squares and cubes. Consequently, the 400th term will be 427-2 =
425.
Answer:
576 Units
Step-by-step explanation:
The way your teacher wants you to do it:
1. We know that multiplying a length by four gives us the perimeter of a square.
1a. Thus, we multiply the given length by four. 4(10x+4)=40x+16
1b. We know the perimeter is 96. So: 40x+16=96
2. Solving for x, we get x=2
3. Plugging our solved x into the given length (10x+4), we see that the length of a side of the square is 10*2+4=24.
4. We know that the area of a square can be found by squaring the side of a square.
4a. 24*24=576.
5. The area is 576 units.
--------------------------------------------------------------
Easier Solution:
1. We know that the perimeter is length*4.
2. We set L to length.
2a. 4L=96
2b. L=24
3. We know that the length square is area.
4. 24*24=576.
Answer:
x = 4
Step-by-step explanation:
The vertex is on the line of symmetry. The zeros are located equidistant from the line of symmetry, which is ...
x = (2 + 6)/2 = 4
The x-coordinate of the vertex is x=4.