Well, the x-intercept is at -4, that means, the graph touches the x-axis at -4, or when x = -4, what's the value of "y" when that happens? well, if the graph touches the x-axis, the y-value has gone all the way down to 0, and thus y = 0, therefore the point at that x-intercept is ( -4, 0 )
so, what's the equation of a line that passes through (-3,2) and (-4,0)?
First we use sin(a+b)= sinacosb+sinbcosa
and cos(a+b)=cosa cosb -sinasinb
tan(x+pi/2)= sin(x+pi/2) / cos(x+pi/2)
and sin(x+pi/2) = sinxcospi/2 + sinpi/2cosx =cosx,
<span>cos(x+pi/2) = cosxcospi/2- sinxsinpi/2= - sinx,
</span> because <span>cospi/2 =0, </span>and <span>sinpi/2=1
</span><span>=tan(x+pi/2)= sin(x+pi/2) / cos(x+pi/2)= cosx / -sinx = -1/tanx = -cotx
</span>from where <span>tan(x+pi/2)=-cotx</span>
Insert 3x - 7 for y in 15x - 5y = 14
15x - 5(3x - 7) = 14
15x - 15x + 35 = 14
0 = -21
There is no solution.
Use the Pythagorean theorem:
