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Mariana [72]
3 years ago
8

I forgot how to convert the inequalities so if someone could please help me that would be great!

Mathematics
1 answer:
jeyben [28]3 years ago
4 0

WHEN GRAPHING

Step 1. Convert to y = mx + b

  • Equation 1: y = 3x/2 - 16/2
  • Equation 2: y = -5 - 2x

Step 2. Graph like normal

  • Find zeros & plot
  • Find y-intercept & plot

Step 3. Shade as indicated by the inequality symbol

  • > or ≥ = above line
  • < or ≤ = below line

Step 4. If  ≤ or ≥ ONLY, then also shade the line

FOR THIS PROBLEM

1. Graph each equation

2. Shade ABOVE line for each

3. Shade line first equation as well

Hope this helps and God bless!

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If possible, which postulate/theorem would prove these two triangles congruent?
mafiozo [28]
AAS, the two angles in the middle are vertical angles and are therefore congruent :)
5 0
3 years ago
Translate: Twice the sum of a number and 3 is equal to five less than the number.
IRINA_888 [86]

Answer:

A.

Twice the sum of a number and three means that the number and three are in parentheses.

4 0
3 years ago
1) (19-16), (-7,-15)​
max2010maxim [7]

Answer:

your answer is -285,112

Step-by-step explanation: first you do this

\frac{y1}{y2} \frac{x1}{x2} \\

the numders should go like this

\frac{-15}{-16} \frac{-7}{19}

then you cross multiply

-15*(19)\\-7*(-16)

the answers to the multiplication

-15*(19)= -285\\-7*(-16)=112

the answer is

-285,112

4 0
3 years ago
2
Kay [80]

Answer:

76

Step-by-step explanation:

140-56= 84

140-84=56

160-84=76

6 0
3 years ago
Please reference the photo below
Art [367]

Answer:

1824

Step-by-step explanation:

200 x (1 + 0.325%)^9 - 1 / 0.325%

200 x (1 + 0.00325)^9 - 1 / 0.00325

200 x 1.00325^9 - 1 / 13/4000

200 x (4013 / 4000)^9 - 1 / 13/4000

200 x 4013^9 / 4000^9 - 1 / 13/4000

200 x 4013^9 - 4000^9 / 4000^9 / 13/4000

200 x 4013^9 - 4000^9 / 13 - 4000^8

4013^9 - 4000^9 / 13 x 20 x 4000^8

4013^9 - 4000^9 / 260 x 4000^8

1823.5

1824

5 0
2 years ago
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