Answer:
Option (3)
Step-by-step explanation:
To prove ΔULV ≅ ΔKLY,
Statements Reasons
1). VL ≅ LY 1). Radii of a circle are equal
2). UL ≅ KL 2). Radii of a circle are equal
3). ∠ULV ≅ ∠KLY 3). Vertical angles are equal
4). ΔULV ≅ ΔKLY 4). SAS property of congruence
Therefore, property (3) given in the options will be used to prove the triangles congruent.
9514 1404 393
Answer:
- Tigers: 8 coaches, 72 players
- Eagles: 16 coaches, 136 players
Step-by-step explanation:
We can define a "basic unit" of each team to be the minimum number of players and coaches that can have the given ratio. For the Tigers, that is 1 coach and 9 players, for a total of 10 team members. For the Eagles, that is 2 coaches and 17 players, for a total of 19 team members. If we have t basic units of Tigers and e basic units of Eagles, then we want ...
10t +19e = 232 . . . . . the total of players and coaches in the two clubs
We want t and e to be integers, so this is a Diophantine equation. It can be solved any of several ways, including use of the Extended Euclidean Algorithm. Here, we'll make some observations based on "number sense."
The value of e must be an even number between 0 and 232/19 = 12. The product of e and 19 must be a number that ends in 2, because 10t will end in 0, and the sum with 19e must end in 2.
The only multiple of 9 that ends in 2 is 9×8 = 72, so the value of e must be a positive number less than 12 that ends in 8. We must have e=8.
Then t=(232 -8×19)/10 = 8. This tells us there are 8 "basic units" of each team.
The Tigers have 8 coaches and 72 players.
The Eagles have 16 coaches and 136 players.
Answer:
i. 
ii. 
Step-by-step explanation:
For each answer, there are only two possible outcomes. Either it is correct, or it is not. The probability of an answer being correct is independent of other answers. So we use the binomial probability distribution to solve this problem.
Binomial probability distribution
Probability of exactly x sucesses on n repeated trials, with p probability.
The expected value of the binomial distribution is:
The standard deviation of the binomial distribution is:
In this problem, we have that:
Each question has four options, one of which is correct. So the probability of getting each answer correct is 
There are 13 questions, so 
i. The mean of the random variable X
ii. The standard deviation of the random variable X
