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Dahasolnce [82]
3 years ago
10

Which integer CANNOT be a solution to the inequality 6x − 4 ≤ 7x − 3 ?

Mathematics
1 answer:
mezya [45]3 years ago
4 0

Answer:

0

Step-by-step explanation:

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Please help me on this <br><br> Simplify (12^2)^4
nika2105 [10]

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7 0
3 years ago
Write the equation of a line perpendicular to y= -1/3x + 5 and passes through the point (6, 4).
Levart [38]

Answer:

y = 3x - 14

Step-by-step explanation:

Perpendicular lines will have a opposite reciprocal slope, so the slope will be 3.

Plug in the slope and given point into y = mx + b, then solve for b:

y = mx + b

4 = 3(6) + b

4 = 18 + b

-14 = b

Plug in the slope and y intercept into y = mx + b

y = 3x - 14

So, the equation of the line is y = 3x - 14

3 0
2 years ago
Which of the following best describes the
ehidna [41]
k:6x-14y=-28\ \ \ \ |subtract\ 6x\ from\ both\ sides\\\\-14y=-6x-28\ \ \ \ \ \ |divide\ both\ sides\ by\ (-14)\\\\y=\frac{-6}{-14}x-\frac{28}{-14}\\\\y=\frac{3}{7}x+2\\----------------------------\\l:3y-7x=-14\ \ \ \ \ |add\ 7x\ to\ both\ sides\\\\3y=7x-14\ \ \ \ \ \ |divide\ both\ sides\ by\ 3\\\\y=\frac{7}{3}x-\frac{14}{3}

Two\ lines\ are\ perpendicular\ if\ product\ of\ the\ slopes\ is\ equal\ -1.\\\\k:y=\frac{3}{7}x+2\to the\ skolpe\ m_k=\frac{3}{7}\\\\l:y=\frac{7}{3}x-\frac{14}{3}\to the\ slope\ m_l=\frac{7}{3}\\\\m_k\times m_l=\frac{3}{7}\times\frac{7}{3}=1\neq-1\\\\conclusion:the\ lines\ are\ not\ perpendicular\\\\Two\ lines\ are\ parallel\ if\ the\ slopes\ are\ equal.\\\\m_k=\frac{3}{7};\ m_l=\frac{7}{3}\to m_k\neq m_l\\\\conclusion:the\ lines\ are\ not\ parallel


Answer:\boxed{C-The\ lines\ intersect\ but\ are\ not\ perpendicular.}
3 0
3 years ago
Read 2 more answers
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