Answer:
use the formula of centroid that is
= x1+x2+x3/3
Answer:
1. x2 - 9 > 0
x^2-3^2>0
(x+3)(x-3)>0
(x+3)>0 and (x-3)>0
x>-3 and x>3
2. x2 - 8x + 12 > 0
x^2 - 8x +12>0
x^2 -2x -6x +12 >0 (-8x is replaced by (-2x) + (-6x) )
x(x-2) -6(x-2) >0
(x-6)(x-2)>0
(x-6)>0 and (x-2)>0
x>6 and x>2
3. -x2 - 12x - 32 > 0
-x^2 -12x -32 >0
x^2 +12x +32 <0
x^2 +4x +8x +32<0
x(x+4) +8(x+4)<0
(x+8)(x+4)<0
(x+8)<0 and (x+4)<0
x<-8 and x<-4
4. x2 + 3x - 20 >= 3x + 5
x^2 +3x -20 >= 3x +5
x^2 +3x -20 -3x >= 3x +5 -3x
x^2 -20 >= 5
x^2 -20 +20 >= 5 +20
x^2 >=25
x^2-25 >=0
(x-5)(x+5)>=0
(x-5)>=0 and (x+5)>=0
x>=5 and x>=-5
<span>
factor a trinomial to (10+x) (8+x)
hope it helps</span>
Answer: y = -4x + 4
<u>Step-by-step explanation:</u>
use the product formula (ab' + a'b) to find the derivative:
x * (1 - 2x)³
a = x a' = 1
b = (1 - 2x)³ b' = 3(-2)(1 - 2x)²
= -6(1 - 2x)²
<u>ab' + a'b</u>
= x(-6)(1 - 2x)² + 1(x)
= -6x(1 - 2x)² + x
Plug in the given x-values to find the slope:
= -6(1)(1 - 2(1))² + (1)
= -6(-1)² + 1
= -6 + 1
= -5
Next, input the slope and the point into the Point-Slope formula:
y + 1 = -5(x - 1)
y + 1 = -4x + 5
y = -4x + 4
