6 + 5.50h = 8.50h<br> PLEASEEE helppp!!!!!!!

Please help if you want brianleist!! :) uhm don't mind update- NO LINkS child..<br> Ty!

GrogVix [38]

12 since there are 12 x’s:)

3 0

3 years ago

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How do you solve x+6/11=10/11

laiz [17]

Answer:

Step-by-step explanation:

x+6/11=10/11

This is a linear equation, because x has no power, so it will be solved by making x the subject of the equation.

Make x the subject

x+6/11=10/11

x=-6/11+10/11

x=10/11-6/11

Since both fractions have the same denominator, the LCM remains 11

x=(10-6)/11

x=4/11

To check if the answer is correct, we substitute x for 4/11 in the equation. And both sides of the equation must be equal

x+6/11=10/11

4/11+6/11=10/11

(4+6)/11=10/11

10/11=10/11

7 0

3 years ago

Find parametric equations for the path of a particle that moves along the circle x2 + (y − 1)2 = 16 in the manner described. (En

ArbitrLikvidat [17]

Answer:

a) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ , b) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ , c) $x = 4\cdot \cos \left(t+\frac{\pi}{2} \right)$ , $y = 1 + 4\cdot \sin \left(t + \frac{\pi}{2} \right)$ .

Step-by-step explanation:

The equation of the circle is:

$x^{2} + (y-1)^{2} = 16$

After some algebraic and trigonometric handling:

$\frac{x^{2}}{16} + \frac{(y-1)^{2}}{16} = 1$

$\frac{x^{2}}{16} + \frac{(y-1)^{2}}{16} = \cos^{2} t + \sin^{2} t$

Where:

$\frac{x}{4} = \cos t$

$\frac{y-1}{4} = \sin t$

Finally,

$x = 4\cdot \cos t$

$y = 1 + 4\cdot \sin t$

a) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ .

b) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ .

c) $x = 4\cdot \cos t''$ , $y = 1 + 4\cdot \sin t''$

Where:

$4\cdot \cos t' = 0$

$1 + 4\cdot \sin t' = 5$

The solution is $t' = \frac{\pi}{2}$

The parametric equations are:

$x = 4\cdot \cos \left(t+\frac{\pi}{2} \right)$

$y = 1 + 4\cdot \sin \left(t + \frac{\pi}{2} \right)$

7 0

3 years ago

5 cm 2 cm 2 cm 5 cm What is the perimeter of the shape?

nata0808 [166]

Answer:

14 cm

All you have to do is add the four sides up and you're good to go! :)

6 0

3 years ago

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what would it be if the sum of six consecutive even numbers is 130 what would the 2nd number be in the sequence PLZ HELP

zubka84 [21]

Answer:

$\huge\boxed{Second\ Number = 42}$

Step-by-step explanation:

Let the consecutive even numbers be x,x+2,x+4, x+ 6, x+ 8 and x+10

So, the given condition is:

x+x+2+x+4+x+6+x+8+x+10 = 270

6x + 30 = 270

Subtracting both sides by 30

6x = 270 - 30

6x = 240

Dividing both sides by 6

x = 40

So,

First Number = x = 40

Second Number = x+2 = 40+2 = 42

Third Number = x+4 = 40+4 = 44

Fourth Number = x+6 = 40+6 = 46

Fifth Number = x+8 = 40+8 = 48

Sixth Number = x+10 = 40+10 = 50

4 0

3 years ago

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6 + 5.50h = 8.50h PLEASEEE helppp!!!!!!!