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atroni [7]
2 years ago
7

6 + 5.50h = 8.50h PLEASEEE helppp!!!!!!!

Mathematics
1 answer:
Ira Lisetskai [31]2 years ago
3 0
The answer is h=2 :)
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Claire has $300 Is an account. She decides she is going to take out $25 each month.
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Recursive equation would be f(x+1) = f(x) - 25 with f(0) = 300

Explicit equation would be f(x) = -25x + 300

And graph would looks like this: 

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Which of these is divisible by 3 and 4?
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One number that is divisible by both 3 and 4 is 12. Any multiple of 12 is also divisible by both 3 and 4, such as 24, 36, 48, etc.
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2 years ago
Joanie bought a total of 56 presents to put in 7 gift bags.She put 3 pencils and an equal number of stickers in each bag.How man
amid [387]

Answer:

5 stickers were put in each bag.

Step-by-step explanation:

There is a total of 56 presents and 7 gift bags. If she puts three pencils in each bag, 7 times 3 is 21. 56 presents minus 21 pencils is 35 presents left. 35 divided by 7 is 5, so there are 5 stickers in each bag.

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2 years ago
Will mark brainly :)
WARRIOR [948]

Answer:

If is positive, then the parabola opens upward, so the function decreases on and increases on . But if is negative, then just the reverse

7 0
2 years ago
4. Diego is thinking of two positive numbers. He says, "If we triple the first number and
aleksandr82 [10.1K]

Answer:

3<em>x </em>+ 2<em>y</em> = 34. and two possible pairs of positive numbers are  (<em>x</em>, <em>y</em>) = (10, 2) and (<em>x</em>, <em>y</em>) = (4, 11).

Step-by-step explanation:

 Let the First positive number be <em>x</em> and second positive number be <em>y.</em>

Triple of first number = 3<em>x</em>

double of second number = 2<em>y</em>

According to question,

3<em>x </em>+ 2<em>y</em> = 34

Therefore, the equation is 3<em>x </em>+ 2<em>y</em> = 34

So the two possible pair of numbers Diego would be thinking of must satisfy the equation 3<em>x </em>+ 2<em>y</em> = 34

Now,  3<em>x </em>+ 2<em>y</em> = 34

3<em>x </em>= 34 - 2<em>y</em>

Let x = 10 and by substituting its value in above expression,

3 \times 10 = 34 - 2y

30 = 34 - 2y

2y = 34 - 30

2y = 4

y = 2

Therefore first pair (<em>x</em>, <em>y</em>) = (10, 2)

In the same way put x = 4 then,

3<em>x </em>= 34 - 2<em>y</em>

3 \times 4 = 34 - 2y

2y = 34 - 12

2y = 22

y = 11

Therefore first pair (<em>x</em>, <em>y</em>) = (4, 11)

Therefore, (<em>x</em>, <em>y</em>) = (4, 11) and  (<em>x</em>, <em>y</em>) = (10, 2) are the two possible pairs of numbers Diego could be thinking of as these both values satisfy the equation 3<em>x </em>+ 2<em>y</em> = 34.  

8 0
2 years ago
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