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Oksi-84 [34.3K]
2 years ago
9

Henry has x blue pens. Rachel has $5$ blue pens and $y$ black pens. Jake has $3$ times the total number of pens Henry and Rachel

have. Write a simplified expression for the number of pens Jake has.
pen(s)
Mathematics
1 answer:
Troyanec [42]2 years ago
4 0

Answer:

Step-by-step explanation:

Henry X blue

Rachel 5 blue and Y black

Jack 3 times the total of pens ( blue & black)

So

X + 5 + Y for Henry and Rachel

Jack : 3( X + 5 + Y)

Jack has 3X + 15 + 3Y.

Pens of jack 3X + 15 Blue & 3Y black.

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Find f(3). <br><br>A. f(3)=6<br><br>B. f(3)=-6<br><br>C. f(3)=0<br><br>D. f(3) is undefined.
forsale [732]

Answer:

A

Step-by-step explanation:

3 0
3 years ago
What is the Compound Inequality that is true for the missing side length? 3cm, 4cm, Xcm
Brrunno [24]

Answer:

x< 3+4\: and\\\left | 3-4 \right |

Step-by-step explanation:

1. Well, when it comes to triangles. Mainly Pythagorean Triple, right triangles whose sides are 3,4,5 or  5,11,12

2. Keeping in mind this a Pythagorean Triple, then x=5

3. Then we can write it as Compound Inequality by combining the Statements for an Inequality of Triangle:

We can write it as

5

Or we can do:

4

and:

3

4. Writing in terms of x:

x

3 0
4 years ago
Each grade level at Hooperville Schools has 298 students.
madreJ [45]

Answer:

(a) 3,874 students.

(b) 46,488 students.

Step-by-step explanation:

We have been given the each grade level at Hooperville Schools has 298 students.

(a) To find the number of students that attend Hooperville Schools, we will multiply the number of grades by 298.

\text{Students that attend Hooperville Schools}=13\times 298

\text{Students that attend Hooperville Schools}=3,874

Therefore, 3,874 students attend Hooperville Schools.

(b) We have been given that nearby district, Willington, is much larger. They have 12 times as many students.

To find the number of students that attend schools in Willington, we will multiply number of students at Hooperville schools by 12.

\text{Students that attend Willington Schools}=12\times 3,874

\text{Students that attend Willington Schools}=46,488

Therefore, 46,488 students attend schools in Willington.

4 0
3 years ago
Take a factor out of the square root:<br> sqrt(3y^2) , where y&lt;0
elena-s [515]

factor took out was y^2 , And resultant expression is  y\sqrt{3} .

<u>Step-by-step explanation:</u>

Here we need to Take a factor out of the square root:  sqrt(3y^2) , where y<0 .Let's do this :

The given expression is  sqrt(3y^2) or , \sqrt{(3y^2)}

We know that , to take out a factor out of the square root that factor must have a degree in multiple of 2 , as   x^2,x^4,x^16,(x+6)^2,(x-2)^4  etc . So ,

⇒ \sqrt{3y^2}

⇒ \sqrt{3}(\sqrt{y^2})

⇒ \sqrt{3}(y^2)^{\frac{1}{2}

⇒ \sqrt{3}(y)^{\frac{2}{2}

⇒ y\sqrt{3}

Therefore , factor took out was y^2 , And resultant expression is  y\sqrt{3} .

5 0
3 years ago
Read 2 more answers
C is the point (-301, 601)<br> Does C lie on the straight line passing through A and B?
Marat540 [252]

Answer:

There is no picture or graph to go with the question so I am afraid I will not be able to give you a specific answer.

To find out if a point (x, y) is on the graph of a line, we plug in the values into that equation and see if we get a true statement, such as 10 = 10. If we get something different, like 6 = 4, we know that the point is not on the line because it does not satisfy the equation. Plug in (-301, 601) into the equation of the line to see whether that point lies on it or not.

Step-by-step explanation:

Suppose the equation of the straight line that passes through E and F is this:

y = 7x + 2

We are to figure out whether or not the point (1, 10) lies on that line. In order to do this we would plug in (1, 10) into the equation, with 1 being x and 10 being y.

10 = 7(1) + 2 = 7 + 2 = 9

10 = 9 is a false statement. Therefore, the point (1, 10) does NOT lie on the line y = 7x + 2.

If you were to provide an image or graph that shows the equation of line AB then perhaps I would be able to answer your question with a specific answer.

8 0
2 years ago
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