Area is a squared number. We know that from the label we use when we solve problems involving area. Perimeter is a single unit label. This single unit label can also be used to find scale factor, since single unit labels are one-to-one. If the area of polygon F is 36, that means that the single unit measure was a number that was squared to get to the area. Same goes for polygon G. That means that in order to find the single unit measure of each of those we have to take the square root of the area. The square root of 36 is 6, and the square root of 4 is 2. 6:2 is the scale factor, but that can be reduced to 3:1, larger to smaller.
Answer:
$1,061
Step-by-step explanation:
Simply find out 2% of the value before, then do that two times more.
21.27*40= Annual premium is 850.8 51% of 850.8 is 433.9 ---> semi annual his quarterly is 26% of 850.8 so 221.2 and finally his monthly premium is 9 percent of 850.8 so it's 76.57
Answer:
No solution
Step-by-step explanation:

Answer: 0.1357
Step-by-step explanation:
Given : Monitors manufactured by TSI Electronics have life spans that have a normal distribution with a variance of
and a mean life span of
hours.
Here , 
Let x represents the life span of a monitor.
Then , the probability that the life span of the monitor will be more than 14,650 hours will be :-
![P(x>14650)=P(\dfrac{x-\mu}{\sigma}>\dfrac{14650-13000}{1500})\\\\=P(z>1.1)=1-P(z\leq1.1)\ \ [\because\ P(Z>z)=1-P(Z\leq z)]\\\\=1-0.8643339=0.1356661\approx0.1357](https://tex.z-dn.net/?f=P%28x%3E14650%29%3DP%28%5Cdfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D%3E%5Cdfrac%7B14650-13000%7D%7B1500%7D%29%5C%5C%5C%5C%3DP%28z%3E1.1%29%3D1-P%28z%5Cleq1.1%29%5C%20%5C%20%5B%5Cbecause%5C%20P%28Z%3Ez%29%3D1-P%28Z%5Cleq%20z%29%5D%5C%5C%5C%5C%3D1-0.8643339%3D0.1356661%5Capprox0.1357)
Hence, the probability that the life span of the monitor will be more than 14,650 hours = 0.1357