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PilotLPTM [1.2K]
3 years ago
5

Hernando’s salary was

Mathematics
2 answers:
Ipatiy [6.2K]3 years ago
6 0

Answer:

11

Step-by-step explanation:

Here's what you do

subtract 44,055 from  49,500

49,500 - 44,055 = 5,445

now you gotta do 5,445 x 100 / 49,500

5,445 x 100 = 544,500

544,500 / 49,500 = 11

11 is your percentage


Here's what itll look like if you want to double check


x             5,445

____X_______

100           49,500

cross multiply and divide

Salsk061 [2.6K]3 years ago
5 0
49500-44055 = 5445

5445/49500 = 0.11 = 11%

There is an 11% change from 49500 to 44055.
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What is the solution to the system of equations graphed below?
zepelin [54]
<span>y = 4x + 11 
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4x + 11 = -2x - 1
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6x = -12
x = -12/6
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</span>y = 4x + 11 
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<span>A. (-2,3)</span>
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3 years ago
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Which statements can be represented by this equation? Select three options.
mars1129 [50]

Answer:

Options A,C and E.

Step-by-step explanation:

The given equation is

2n-9.2=n+\dfrac{4}{5}

Let n be the unknown number, then

Twice a number minus nine and two-tenths is the same as the number plus four-fifths.

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So, option A is correct.

Nine point two decreased by double a number is the same as the number added to four-fifths.

9.2-2n=n+\dfrac{4}{5}

Nine point two less than twice a number is equal to the number added to four-fifths.

2n-9.2=n+\dfrac{4}{5}

So, option C is correct.

Two times the difference of a number and nine and two-tenths is equal to the number plus four-fifths.

2(n-9.2)=n+\dfrac{4}{5}

Double a number decreased by nine and two-tenths is the same as the sum of four-fifths and the number.

2n-9.2=n+\dfrac{4}{5}

So, option E is correct.

Therefore, the correct options are A,C and E.

5 0
3 years ago
Read 2 more answers
Please refer to the attachment​
MariettaO [177]

<u>W</u><u>e</u><u> </u><u>h</u><u>a</u><u>v</u><u>e</u><u>:</u><u>-</u>

  • P=₹26,400
  • R=15% p.a compounded yearly
  • n=2 years and 4 months

\tt \: So,amount \: for \: 2 \: years = p \large(1 +  \frac{r}{100}) {}^{n}

\tt=₹26,400 \large(1 +  \frac{15}{100}) {}^{2}

\tt=₹26,400 \:  \large( \frac{23}{20}) {}^{2}

\tt =₹26,400 \times  \frac{23}{20}  \times  \frac{23}{20} \\

\tt = 66 \times 529=₹34,914

\tt \: So,SI \: for \: 4 \: months =   \frac{P \times R \times n }{100 \times 12}

\tt \: =  \frac{ 34,914 \times 15 \times 4 }{100 \times 12} \\

\tt\boxed{ = 1745.70}

Thus,the amount after 2years and 4months =₹34,914+₹1745.70=₹36,659.70

\bold \red{I \: hope \: this \: may \: help \: you}

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3 years ago
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sattari [20]

Answer:

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