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Severe Droughts can make land unlivable, as all living things need food and water to survive
Answer:
2,981g
Explanation:
Firstly, we need to find the number of moles of MgCl that we have by using the formula: mass = No. Moles x Molar Mass, which we can rearrange so that we are solving for no. moles:
No. Moles = mass / Molar Mass
We are given a mass of 621g, and we can calculate the molar mass of MgCl by adding the two molar masses together: 24.31+35.45 = 59.76
Now we can calculate number of moles by substituting these values into the formula:
n = 621 / 59.76
No. moles = 10.4
Now we can use the co-efficients in the formula to tell us how many moles of AgCl will be formed. The coefficient of MgCl is 1, and the coefficient of AgCl is 2. This means that every 1 mol of MgCl will form 2 moles of AgCl. So, to find the no. moles of AgCl, we multiply our no. moles by 2:
10.4 x 2 = 20.8 moles
Finally we convert this back into mass by multiplying the no. moles by the Molar mass of AgCl:
m = 20.8 x (107.87+35.45)
m = 2,981g
Answer:
The above reaction is an example of <u>alcoholic fermentation</u>.
Explanation:
In alcoholic fermentation, one mole of glucose gets converted into two moles of alcohol, two moles of carbon dioxide and two moles of adenosine tri-phosphate (ATP).
It is usually neutral becase its is close to neutral number 7
Answer:
4.21 g of AgCl
3.06 g of BaCl₂ will be needed to complete the reaction
Explanation:
The first step is to determine the reaction.
Reactants: BaCl₂ and AgNO₃
The products will be the silver chloride (AgCl) and the Ba(NO₃)₂
The reaction is: BaCl₂(aq) + 2AgNO₃(aq) → 2AgCl(s) ↓ + Ba(NO₃)₂ (aq)
We determine the silver nitrate moles: 5 g . 1mol / 169.87 g = 0.0294 moles. Now, according to stoichiometry, we know that ratio is 2:2-
2 moles of nitrate can produce 2 moles of chloride, so the 0.0294 moles of silver nitrate, will produce the same amount of chloride.
We convert the moles to mass → 143.32 g / mol . 0.0294 mol = 4.21 g of AgCl.
Now, we consider the BaCl₂.
2 moles of nitrate can react to 1 mol of barium chloride
Then, 0.0294 moles of silver nitrate will react to (0.0294 . 1) /2 = 0.0147 moles. We convert the moles to mass:
0.0147 mol . 208.23 g /1mol = 3.06 g of BaCl₂
