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katrin [286]
3 years ago
15

30) How many grams of CH3OH must be added to water to prepare 210 mL of a solution that is

Chemistry
1 answer:
gavmur [86]3 years ago
4 0

Answer:

Mass = 10.0 g

Explanation:

Given data:

Molarity = 1.50 M

Volume = 210 mL ( 0.21 L)

Grams of CH₃OH = ?

Solution:

Number of mole = molarity × volume

Number of mole = 1.50 M × 0.21 L

Number of mole = 0.315 mol

Mass of CH₃OH:

Mass = Number of moles ×  molar mass

Mass = 0.315 mol × 32.04 g/mol

Mass = 10.0 g

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What are deltaTb and deltaTf for an aqueous solution that is 1.5g nacl in 0.250kg h2o? Given Kb=0.51 C/m and kr=1.86 C/m
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\Delta T_b = I \times K_b \times m {i- vant hoff’s constant ; Kb- constant ; m molarity }

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