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katrin [286]
2 years ago
15

30) How many grams of CH3OH must be added to water to prepare 210 mL of a solution that is

Chemistry
1 answer:
gavmur [86]2 years ago
4 0

Answer:

Mass = 10.0 g

Explanation:

Given data:

Molarity = 1.50 M

Volume = 210 mL ( 0.21 L)

Grams of CH₃OH = ?

Solution:

Number of mole = molarity × volume

Number of mole = 1.50 M × 0.21 L

Number of mole = 0.315 mol

Mass of CH₃OH:

Mass = Number of moles ×  molar mass

Mass = 0.315 mol × 32.04 g/mol

Mass = 10.0 g

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Aqueous solutions of lithium sulfate and calcium nitrate are mixed, forming the precipitate
Mashcka [7]

Answer:

(aq) Li2SO4 + (aq) Ca(NO3)2 --> (s) CaSO4 + (aq) 2LiNO3

Explanation:

Aqueous Lithium Sulfate is Li2SO4

Aqueous Calcium Nitrate is Ca(NO3)2

When they're mixed, we get the double displacement solution Calcium Sulfate and Lithium Nitrate.

Precipitate is solid.

We got solid Calcium Sulfate so the other solution must be aqueous.

CaSO4 (s) --> Calcium Sulfate product

LiNO3 (aq) --> Lithium Nitrate product

We balance equation now. 2 Lithiums total and 2 Nitrates total. (Cuz there are 2 on the other side, 1 here)

4 0
2 years ago
The branch of chemistry that looks at the release of electrical energy is called
sergij07 [2.7K]
B is the correct answer tbh
3 0
3 years ago
How many nitrogen atoms are in 2.79 mo.of NH3
alexandr1967 [171]
1 mol of any particles has 6.02 * 10 ²³ particles.

If we look at 1 NH3 (1 mol NH3 or 1 molecule NH3), we can see that 1 molecule NH3 has 1 atom of N and 3 atoms of H; also 1 mole of NH3 has 1 mole of N atoms and 3 moles of H atoms.

So, 1 mol of NH3 has 1 mol of N atoms,
 and 2.79 mol NH3 have 2.79 mol of N atoms.

2.79 mol of N atoms* 6.02 * 10 ²³ N atoms/ 1 mol N atoms = 1.68*10²⁴ N-atoms 

 Answer is 1.68*10²⁴ N-atoms. 
5 0
3 years ago
What is the concentration of 60 mL of H3PO4 if it is neutralized by 225 mL of 2 M Ba(OH)2?
goldfiish [28.3K]

7.5 M is the concentration of 60 ml of H3PO4 if it is neutralized by 225 ml of 2 M Ba(OH)2.

Explanation:

Data given:

volume of phosphoric acid, Vacid =60 ml

volume of barium hydroxide, Vbase = 225 ml

molarity of barium hydroxide, Mbase = 2M

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the formula for titration is used as:

Macid x Vacid = Mbase x Vbase

rearranging the equation to get Macid

Macid = \frac{Mbase x Vbase}{Vacid}

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the concentration of the phosphoric acid is 7.5 M and the volume is 60 ml. Thus 7.5 M solution of phosphoric acid is used to neutralize the barium hydroxide solution of 2M.

8 0
3 years ago
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What average global temperature is maintained when there is a balance in Earth’s energy budget?
Thepotemich [5.8K]
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8 0
2 years ago
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