Question

Suppose that one of millikan's oil drops has a charge of −4.8×10−19

Answer 1

The best and correct option is c

Answer 2

Answer: The number of excess electrons that the drop contains are 3.

Explanation:

We are given:

Charge on millikan's oil drops = $4.8\times 10^{-19}C$

To calculate the number of excess electrons, we divide the charge on millikan's oil drop by the change on 1 electron.

$\text{Excess electrons}=\frac{\text{Charge on millikan's oil drop}}{\text{Charge on 1 electron}}$

We know that:

Charge on 1 electron = $1.60\times 10^{-19}C$

Putting values in above equation, we get:

$\text{Excess electrons}=\frac{4.8\times 10^{-19}C}{1.60\times 10^{-19}C}\\\\\text{Excess electrons}=3$

Hence, the number of excess electrons that the drop contains are 3.