The final temperature of the water is determined as 50.55 ⁰C.
<h3>
Final temperature of the water</h3>
The final temperature of the water is determined from the following calculations;
Q = mcΔθ
Δθ = Q/mc
where;
- Q is the amount of energy = 81 kcal = 338904 J
- c is specific heat capacity of water = 4,200 J/kgC
Δθ = 338904 /(3.5 x 4200)
Δθ = 23.05 °C
Final temperature = T₁ + Δθ
Final temperature = 27.5°C + 23.05 °C = 50.55 ⁰C.
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Answer:
a. 6 mol of oxygen
b. 10 mol of iron(III)oxide
Explanation:
Use mole concept.
Answer:
5.83 mol.
Explanation:
- From the balanced reaction:
<em>2Al + 3Ag₂S → 6Ag + Al₂S₃,</em>
It is clear that 2 mol of Al react with 3 mol of Ag₂S to produce 1 mol of Ag and 1 mol of Al₂S₃.
Al reacts with Ag₂S with (2: 3) molar ratio.
<em>So, 2.27 mol of Al reacts completely with 3.4 mol of Ag₂S with (2: 3) molar ratio.</em>
<em />
- The limiting reactant is Ag₂S.
- The excess "left over" reactant is Al.
The reamining moles of excess reactant "Al" = 8.1 mol - 2.27 mol = 5.83 mol.
Answer:
For H-Cl, the direction is towards the chlorine atom
For F-CH3, the direction is towards the flourine atom.
Explanation:
The dipole moment is a vector quantity. This implies that it has both magnitude and direction.
Thus, the direction of the dipole moment always points from the positive atom towards the negative atom.
This explains the fact that it points to chlorine in HCl and points to flourine in F-CH3
I don't know this article, but I do know some major changes: first, the change from the plum pudding model (no nucleus, just electrons) to the gold foil experiment, which had Rutherford shoot alpha particles at a sheet of gold only to find them rebounding, proving the existence of a positively charged mass, i.e a nucleus, in the atom. However, this changed again when Bohr realized that the negatively charged electrons should be attracted to the positively charged center, so that there must be something else inside the nucleus.
