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Leno4ka [110]
2 years ago
13

Type the correct answer in the box. use numerals instead of words. if necessary, use / for the function bar. polygon MNOPQ is di

lated by a scale factor of 0.8 with the origin as the center of dilation. resulting in the image M'N'OP'Q. The coordinates of point M are (2,4) and the coordinates of point N are (3,5) .
THE SLOPE OF M'N' is blank
Mathematics
1 answer:
lorasvet [3.4K]2 years ago
8 0

Answer: 1

Step-by-step explanation:

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The statistical difference between a process operating at a 5 sigma level and a process operating at a 6 sigma level is markedly
Svet_ta [14]

Answer:

True

Step-by-step explanation:

A six sigma level has a lower and upper specification limits between \\ (\mu - 6\sigma) and \\ (\mu + 6\sigma). It means that the probability of finding no defects in a process is, considering 12 significant figures, for values symmetrically covered for standard deviations from the mean of a normal distribution:

\\ p = F(\mu + 6\sigma) - F(\mu - 6\sigma) = 0.999999998027

For those with defects <em>operating at a 6 sigma level, </em>the probability is:

\\ 1 - p = 1 - 0.999999998027 = 0.000000001973

Similarly, for finding <em>no defects</em> in a 5 sigma level, we have:

\\ p = F(\mu + 5\sigma) - F(\mu - 5\sigma) = 0.999999426697.

The probability of defects is:

\\ 1 - p = 1 - 0.999999426697 = 0.000000573303

Well, the defects present in a six sigma level and a five sigma level are, respectively:

\\ {6\sigma} = 0.000000001973 = 1.973 * 10^{-9} \approx \frac{2}{10^9} \approx \frac{2}{1000000000}

\\ {5\sigma} = 0.000000573303 = 5.73303 * 10^{-7} \approx \frac{6}{10^7} \approx \frac{6}{10000000}  

Then, comparing both fractions, we can confirm that a <em>6 sigma level is markedly different when it comes to the number of defects present:</em>

\\ {6\sigma} \approx \frac{2}{10^9} [1]

\\ {5\sigma} \approx \frac{6}{10^7} = \frac{6}{10^7}*\frac{10^2}{10^2}=\frac{600}{10^9} [2]

Comparing [1] and [2], a six sigma process has <em>2 defects per billion</em> opportunities, whereas a five sigma process has <em>600 defects per billion</em> opportunities.

8 0
3 years ago
SOMEONE PLEASE HELP I will give you brainliest it’s due in 11:59 pm TODAY!! Please
Snezhnost [94]
Shorter side: 130ft
longer side: 260ft
greatest possible area: 33800ft^2

basically get the equations for area and perimeter which will be

A: lw (length x width)
P: l + 2w

Substitute them into eachother and you get the equation:
-2w^2+520w = A

find the vertex of this parabola which will give you the greatest width which is 130m
Then u can find length and area from this width
4 0
3 years ago
Read 2 more answers
0.79 x 3.7 =<br> please explain your process
mart [117]

This question is super easy.

0.79*3.7

=2.923

Hope this helps!

Thanks!

-Charlie

3 0
3 years ago
A fire hydrant with a blue cap provides water at a rate of 1,500 gallons per minute. A fire hydrant with a green cap provides wa
ivann1987 [24]

Answer: 2b = 3g

Step-by-step explanation:

This is quite basic to solve, below is a Step by step explanation:

from the given question we have that;

  • A fire hydrant with a blue cap provides water at a rate of 1,500 gallons per minute.

       i.e  b = 1500 gallons per minute

  • A fire hydrant with a green cap provides water at a rate of 1,000 gallons per minute.

          g = 1000 gallons per minute.

Our questions tells us to write the equation which  relates the flow of water from the blue hydrant, b, to the flow from the green hydrant, g.

ANS:

Since flow from blue  hydrant b = 1500 gallons per minute, we have that

b = 3 * 500

b = 3 * 1000/2 g

b = 3/2 g

equation  gives 2b = 2g

cheers i hope this helped !!

5 0
3 years ago
1) Solve for x in the following equation: 7x + 10 - 10x - 5 &gt; 20 *
Olenka [21]

Answer:x<1/7 (5 - sqrt(130))

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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