All categories

2 years ago

PLEASE HELP ASAP ON MY MATH!!

Mathematics

2 answers:

neonofarm [45]2 years ago

8 0

Answer:

( 16 × 8 )-40

128 -40

=87 square feet

Allisa [31]2 years ago

7 0

Answer:

Area of shaded region=41 square feet

Area of non shaded region= 87 square feet

Step-by-step explanation:

As, Shaded area is made of different shapes including two rectangles and one triangle

So,

Area of shaded region,

$=(8\times2)+(10\times 1)+(\frac{1}{2}\times 3\times10)\\\\ =16+10+15=41 \quad \text{square feet}$

Area of non shaded region=total area of rectangular region-Shaded region

$=(16\times 8)-(41)\\=128-41\\=87 \quad \text{square feet}$

You might be interested in

Identifying the values a, b, and c is the first step in using the Quadratic Formula to find solution(s) to a quadratic equation.

MatroZZZ [7]

Answer:

To find a b and c in a quadratic equation, the x^2 number is a, so 7x^2 is your a value, your b value is just the x, so your b value is -9, and your c value is the regular number, which is 18. a=7x^2 b=-9x c = 18. So your answer is answer B.

Step-by-step explanation:

6 0

3 years ago

I have 7 different geography textbooks and 4 different chemistry textbooks. In how many ways can I line the 11 textbooks on a bo

saveliy_v [14]

Answer:

120960

Step-by-step explanation:

We get 11 books 7 of geography and 4 of chemistry

We need to line all of them with 2 constraints

1.-three of the geography must be: 1 in the middle and in each end, then we already have

C₄,₃ = 4! / ( 4 - 3 ) ! C₄,₃ = 4*3*2*1

C₄,₃ = 24 different ways

Now we have 7 books of chemistry. To place them we get

P₇ = 7! P₇ = 7*6*5*4*3*2*1 P₇ = 5040

Now the total number will be

C₄,₃* P₇ = 120960

7 0

4 years ago

HELPPPP !!! VERY URGENT!!!!<br> HIGH POINTS

Blababa [14]

The answer is 9 I hope I am not late to this question sorry if I am wrong,

4 0

3 years ago

Find [5(cos 330 degrees + I sin 330 degrees)]^3

earnstyle [38]

Given a complex number in the form:
$z= \rho [\cos \theta + i \sin \theta]$
The nth-power of this number, $z^n$ , can be calculated as follows:

- the modulus of $z^n$ is equal to the nth-power of the modulus of z, while the angle of $z^n$ is equal to n multiplied the angle of z, so:
$z^n = \rho^n [\cos n\theta + i \sin n\theta ]$
In our case, n=3, so $z^3$ is equal to
$z^3 = \rho^3 [\cos 3 \theta + i \sin 3 \theta ] = (5^3) [\cos (3 \cdot 330^{\circ}) + i \sin (3 \cdot 330^{\circ}) ]$ (1)
And since
$3 \cdot 330^{\circ} = 990^{\circ} = 2\pi +270^{\circ}$
and both sine and cosine are periodic in $2 \pi$ , (1) becomes
$z^3 = 125 [\cos 270^{\circ} + i \sin 270^{\circ} ]$

6 0

4 years ago

Help needed ASAP will give brainliest

Rom4ik [11]

Answer:

-5

Step-by-step explanation:

counting is like backwards in negatives so a +5 is slow and a +25 is high but in negatives its the opposite because you are missing that many

I dont really know who to explain it but I hope this helps

5 0

4 years ago