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maw [93]
2 years ago
15

Find the amount of time. I=$237. 90, P=$1525, r=2. 6% Find the amount of time. __ Years

Mathematics
1 answer:
Virty [35]2 years ago
3 0

~~~~~~ \textit{Simple Interest Earned} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\dotfill & \$237.90\\ P=\textit{original amount deposited}\dotfill & \$1525\\ r=rate\to 2.6\%\to \frac{2.6}{100}\dotfill &0.026\\ t=years \end{cases} \\\\\\ 237.90 = (1525)(0.026)(t)\implies \cfrac{237.90}{(1525)(0.026)}=t \implies 6=t

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Ray UW is the angle bisector of AngleVUT.
tester [92]

Answer:

AngleWUT =38°, option 2

Step-by-step explanation:

We have three rays passing through U. A ray is set extend in one direction with one fixed point.

We have UW ray bisecting VUT.As the ray bisects the angle between VUW and WUT would be same .

Given angles are (4x+6)° and (6x-10)°.

As these angles are equal

4x+6=6x-10

2x=16

x=8

AngleWUT = (6x – 10)°

and x is 8 so on substituting AngleWUT =38°.

5 0
3 years ago
Read 2 more answers
Help! due in 2hrs please show work :)
Sidana [21]

Answer:

Its A

Step-by-step explanation:

7 0
3 years ago
Carl has three lengths of cable, 5/6 yard long, 1/4 yard long, and 2/3 yard long. If he uses 1 yard of cable, how much cable is
Dafna1 [17]
He would have 9/12 yards left over because you have to create a common denominator which would be 12. so for 5/6 you would multiply by 2 so you have 10/12. 1/4 you have to multiply by 3 so you get 3/12. and 2/3 you have to multiply by 4 so you get 8/12. then you add them 10/12+3/12+8/12 = 21/12 which simplifies to 1 9/12 and because he used 1 yard he is left with 9/12.
final answer: 9/12 yards
3 0
3 years ago
ANSWERED
kvv77 [185]

Answer:

c but you have it so thanks

Step-by-step explanation:

6 0
3 years ago
Among 35 students in a class, 20 of them earned A's on the midterm exam, 13 earned A's on the nal exam, and 12 did not earn A's
enyata [817]

Answer:

The correct answer is "\frac{2}{7}".

Step-by-step explanation:

According to the question,

Number of students,

= 35

A ! mid term A,

n(A) = 20

B : final A,

n(B) = 13

Didn't start,

n(A^c \cap B^c) = 12

Now,

⇒ n(A \cup B)=35-12

                   =23

then,

⇒ n(A \cup B)=20+13-23

                   =10

hence,

The probability will be:

⇒ P(A \cap B)=\frac{10}{35}

⇒                 =\frac{2}{7}

7 0
3 years ago
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