Answer:
Step-by-step explanation:
Principal, P = $4,000
Interest rate, r = 3% = 0.03
Period, t = 20 years
Number of times compounded in a year = 4
Amount , A = P( 1 + r/n)^tn
A = 4000( 1 + 0.03/4)^4*20
A = 4000( 1 + 0.0075) ^80
A =4000( 1.0075) ^80
A = 4000* 1.818
A = $7272.18
10k^4+10k^3+8k^2+8k+10/k+1 not sure if this is what you are looking for or not hope it helps
Answer:
a) 29
b) 0
c) 7
d) 3/8
Step-by-step explanation:
Whenever you're facing a clock maths problem, the solution always have to be < to the number of hours in the given clock. If it's > the number of hours of the given clock, you subtract the number of hours until you get a result <= the number of clock hours.
If the result is negative, you add the clock hours.
a) 21 - 33 = -12 , so -12 + 41 = 29
b) 13 * 4 = 52, then do 52 - 52 = 0, since answer has to be < 52.
c) 11+19 = 30, 30 - 23 = 7
d) 3/8 = 3/8, since 3/8 <= 15, you're also fine.
