Answer:
the second answer/option is right
Taking into account the definition of Avogadro's Number, 7.80×10²² molecules of HCl are contained in 0.1295 moles of HCl.
<h3>
Avogadro's Number</h3>
Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023×10²³ particles per mole. Avogadro's number applies to any substance.
<h3>This case</h3>
Then you can apply the following rule of three: if 6.023×10²³ molecules are contained in 1 mole of HCl, then 7.80×10²² molecules are contained in how many moles of HCl?
amount of moles of HCl= (7.80×10²² molecules × 1 mole)÷ 6.023×10²³ molecules
<u><em>amount of moles of HCl= 0.1295 moles</em></u>
Finally, 7.80×10²² molecules of HCl are contained in 0.1295 moles of HCl.
Learn more about Avogadro's Number:
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<u>brainly.com/question/1528951?referrer=searchResults</u>
The probability that X is greater than 70 and less than 90 is; 0.85
<h3>How to find the probability?</h3>
Let X be the binomial random variable with the parameters:
n = 200
p = 0.4
Then, the random variable Z defined as:
Z = (X - np)/(√(np(1 - p)
The probability that X is greater than 70 and less than 90 is expressed as; P(70 < X < 90)
At X = 70, we have;
Z = (70 - (200*0.4))/(√(200 * 0.4(1 - 0.4))
Z = -1.44
At X = 90, we have;
Z = (90 - (200*0.4))/(√(200 * 0.4(1 - 0.4))
Z = 1.44
Thus, the probability would be expressed as;
P(-1.44 < Z < 1.44)
From online p-value calculator, we have;
P(-1.44 < Z < 1.44) = 0.85
Complete question is;
Suppose that X is a binomial random variable with n = 200 and p = 0.4 Approximate the probability that X is greater than 70 and less than 90.
Read more about probability at; brainly.com/question/4621112
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