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2 years ago

In an ordered pair, the y-coordinate tells you how far to move from the origin parallel to the______. X-axis/y-axis

Mathematics

1 answer:

erastova [34]2 years ago

5 0

Answer:

y-axis

Step-by-step explanation:

The x-coordinate is the location of a point as measured along the x-axis. The y-coordinate is the location of a point as measured along the y-axis.

Another way to describe the y-coordinate is that it tells you how far to move from the origin parallel to the y-axis.

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Give the equation of the circle centered at the origin and passing through the point (4,0)

zimovet [89]

Answer:

x² + y² = 4²

Step-by-step explanation:

The standard equation of a circle centered at the origin and with radius r is

x² + y² = r²

Note that the point (4, 0) is 4 units horizontally and to the right of the center (0, 0). Thus, we know immediately that the radius is 4.

Thus the equation of this circle is x² + y² = 4²

4 0

4 years ago

Find c and round to the nearest tenth. thank you in advance

PSYCHO15rus [73]

Answer and Step-by-step explanation:

90ft = a

55ft = b

50ft = c

Plug into equation.

$50^{2} = 90^{2} + 55^{2} - 2(90)(55)cosC\\\\2500 = 11125 - 9900(cosC)\\\\-8625 = -9900(cosC)\\\\0.8712 = cosC\\\\cos^{-1} (0.8712) = C\\\\29.4$

29.4° is the answer.

4 0

3 years ago

Suppose that the mean water hardness of lakes in Kansas is 425 mg/L and these values tend to follow a normal distribution. A lim

tino4ka555 [31]

Answer:

The mean water hardness of lakes in Kansas is 425 mg/L or greater.

Step-by-step explanation:

We are given the following data set:

346, 496, 352, 378, 315, 420, 485, 446, 479, 422, 494, 289, 436, 516, 615, 491, 360, 385, 500, 558, 381, 303, 434, 562, 496

Formula:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{10959}{25} =438.36$

Sum of squares of differences = 175413.76

$S.D = \sqrt{\dfrac{175413.76}{24}} = 85.49$

Population mean, μ = 425 mg/L

Sample mean, $\bar{x}$ = 438.36

Sample size, n = 25

Alpha, α = 0.05

Sample standard deviation, s = 85.49

First, we design the null and the alternate hypothesis

$H_{0}: \mu \geq 425\text{ mg per Litre}\\H_A: \mu < 425\text{ mg per Litre}$

We use one-tailed t test to perform this hypothesis.

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }$

Putting all the values, we have

$t_{stat} = \displaystyle\frac{438.36 - 425}{\frac{85.49}{\sqrt{25}} } = 0.7813$

Now, $t_{critical} \text{ at 0.05 level of significance, 24 degree of freedom } = -1.7108$

Since,

The calculated t-statistic is greater than the critical value, we fail to reject the null hypothesis and accept it.

Thus, the mean water hardness of lakes in Kansas is 425 mg/L or greater.

6 0

3 years ago

Wilfred is feeding his goats. He gives 56% of the bag of feed to the goats in field A and the rest to the goats in field B. If t

krok68 [10]

Answer:

$Feeds = 11.76kg$

Step-by-step explanation:

Given

$Field\ A= 56\%$

$Field\ B= The\ rest$

$Bag = 21kg\ feed$

Required

Determine how much goats in field A, get.

To do this, we simply multiply the percentage feed received by goats in field A by the actual bags of feeds

i.e.

$Feeds = 56\% * 21kg$

Convert percentage to decimal

$Feeds = 0.56 * 21kg$

$Feeds = 11.76kg$

Hence, goats in field A get 11.76kg of feeds

6 0

3 years ago

What is the answer at the bottom?

salantis [7]

Answer:

15n

Step-by-step explanation:

Since it is 15 samples per day, you just need to multiple 15 by the number of days.

5 0

3 years ago

In an ordered pair, the y-coordinate tells you how far to move from the origin parallel to the______. X-axis/y-axis​

In an ordered pair, the y-coordinate tells you how far to move from the origin parallel to the______. X-axis/y-axis