All categories

3 years ago

Algebra 2 See image below for question, and requesting help! (20 points will be given!)

Mathematics

1 answer:

slavikrds [6]3 years ago

6 0

Answer:

x= 5,-3,2

Step-by-step explanation:

one solution is x=5

show that (x^3-4x^2-11x+30)÷(x-5) fraction is 0

and get (x-5)(x^2+5x+6)=(x-5)(x+3)(x-2)

so x=5,-3,2 #

You might be interested in

Find the value of x<br> Please help...no links please

OverLord2011 [107]

Answer:

x=1

Step-by-step explanation:

(7x-1)+(2x-1)=7

7x+2x-1-1=7

7x+2x=7+1+1

9x=9

9x/9 = 9/9

x=1

5 0

3 years ago

How do I do this.?.?.

viktelen [127]

108 = ( x)(48-x)
108 = 48x - x^2
48x -x^2 -108 = 0

I'm assuming you're doing solve the square right now, so you should be able to do the rest.

3 0

3 years ago

Read 2 more answers

Assume the time required to complete a product is normally distributed with a mean 3.2 hours and standard deviation .4 hours. Ho

Alex787 [66]

Answer: 3.712 hours or more

Step-by-step explanation:

Let X be the random variable that denotes the time required to complete a product.

X is normally distributed.

$X\sim N(\mu=3.2\text{ hours},\ \sigma=0.4\text{ hours} )$

Let x be the times it takes to complete a random unit in order to be in the top 10% (right tail) of the time distribution.

Then, $P(\dfrac{X-\mu}{\sigma}>\dfrac{x-\mu}{\sigma})=0.10$

$P(z>\dfrac{x-3.2}{\sigma})=0.10\ \ \ [z=\dfrac{x-\mu}{\sigma}]$

As, $P(z>1.28)=0.10$ [By z-table]

Then,

$\dfrac{x-3.2}{0.4}=1.28\\\\\Rightarrow\ x=0.4\times1.28+3.2\\\\\Rightarrow\ x=3.712$

So, it will take 3.712 hours or more to complete a random unit in order to be in the top 10% (right tail) of the time distribution.

3 0

4 years ago

Identify all the sets to which the number 0.41567. . . . belongs. Choose from rational, irrational, whole, and integer.

Shkiper50 [21]

It will belong only irrational. Hope it help!

6 0

3 years ago

Shelia is dividing x4 – 4x3 + 4x2 – 6x + 5 by x – 1 using a division table. Quotient Divisor x3 – 3x2 + x – 5 x x4 –3x3 x2 A – 1

Hatshy [7]

Is there by answer choice? Or by a table?

4 0

3 years ago