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3 years ago

Show (prove) in detail why (xyz)4 =x4 y4 z4 for any number x,y,z

1 answer:

7 0

By using distributive property you can distribute (XYZ)4 and get a simplified answer of 4(x)+ 4(y) + 4 (z). The parenthesis show that 4(xyz) is not simplified and could also be written as 4(x)+ 4(y) + 4 (z).

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HELP

EleoNora [17]

Answer:

x = 7 & y = 8

Step-by-step explanation:

We know that

Mean = Sum of terms/Total terms

=> Mean = 4 + 6 + x + y + 10/5

=> Mean = 20 + x + y/5

Now,

Median = (n + 1)/2

=> Median = (5 + 1)/2

=> Median = 6/3

=> Median = 3rd term = x

So,

x = 20 + x + y/5

x × 5 = 20 + x + y

5x = 20 + x + y

5x - x = 20 + y

4x = 20 + y

Since x and y are in order so,

Possible outcomes will be 7,8 & 9

(7,8) & (8,9) & (7,9)

Taking x = 7 and y = 8

4(7) = 20 + 8

28 = 28

Hence,

x = 7 and y = 8

5 0

2 years ago

Read 2 more answers

The ratio of pink roses bushes to white rose bushes in the city Garden is about 12 to 15. If there were 92 pink rose bushes, abo

andreyandreev [35.5K]

Answer:

$115\ white\ rose\ bushes$

Step-by-step explanation:

Let

x------> the number of pink roses bushes

y----> the number of white rose bushes

we know that

$\frac{x}{y} =\frac{12}{15}$

$y=\frac{15}{12}x$ -----> equation A

$x=92$

substitute the value of x in the equation A

$y=\frac{15}{12}(92)=115\ white\ rose\ bushes$

8 0

3 years ago

Which fraction is not equivalent to 9/12 a.24/32 b.6/8 c.15/20 d.16/24

stiv31 [10]

The answer is D.

9/12 = 3/4
16/24 = 2/3

2/3 is not equivalent to 3/4

5 0

3 years ago

Suppose that 5 out of 13 people are to be chosen to go on a mission trip. In how many ways can these 5 be chosen if the order in

algol [13]

5 People can be chosen in 1287 ways if the order in which they are chosen is not important.

Step-by-step explanation:

Given:

Total number of students= 13

Number of Students to be selected= 5

To Find :

The number of ways in which the 5 people can be selected=?

Solution:

Let us use the permutation and combination to solve this problem

$nCr=\frac{(n)!}{(n-r)!(r)!}$

So here , n =13 and r=5 ,

So after putting the value of n and r , the equation will be

$13C_5=\frac{(13)!}{(13-5)!(5)!}$

$13C_5=\frac{(13 \times12 \times11 \times10 \times9 \times8\times7 \times6 \times5 \times4 \times3 \times2 \times1)}{(8 \times7 \times6 \times5 \times4 \times3 \times2 \times1)(5 \times4 \times3 \times2 \times1)}$