The function of the object height is an illustration of a projectile motion
The object will never hit the ground
<h3>How to determine when the object hits the ground?</h3>
The function is given as:
h=16t^2+80t+96.
When the object hits the ground, h = 0
So, we have:
16t^2+80t+96 = 0
Divide through by 16
t^2+5t+6 = 0
Expand
t^2 + 3t + 2t + 6 = 0
Factorize
t(t + 3) + 2(t + 3) = 0
Factor out t + 3
(t + 2)(t + 3) = 0
Solve for t
t = -2 or t = -3
The time (t) cannot be negative.
Hence, the object will never hit the ground
Read more about projectile motion at:
brainly.com/question/1130127
Answer:
y = -2x+1
Step-by-step explanation:
We have a point and a slope, so we can use the point slope form of a line
y-y1 = m(x-x1) where m is the slope and (x1,y1) is the point
y-3 = -2(x--1)
y-3=-2(x+1)
Distribute the 2
y-3 = -2x-2
Add 3 to each side
y-3+3 = -2x-2+3
y = -2x+1
This is in slope intercept form
Answer:
UINJIBIDHUOSHBIDUNSIUSNIJKDNUHFJDOUUODSJDJSNNSJg
Step-by-step explanation:
A because the square is in the (10) place and the circle is in the (1) place and 10 is 10 times bigger than 1
