Зл Given that tan a=-1, what is the value of sece, for 2 - 2 O2 0 0 O 1
1 answer:
You might be interested in
Answer:
The 95% confidence interval of for this random sample is between 128.16 calories and 139.84 calories. This means that we are 95% that the mean number of calories for all bags of potato chips is in this interval.
Step-by-step explanation:
We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 35 - 1 = 34
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 34 degrees of freedom(y-axis) and a confidence level of . So we have T = 2.0322
The margin of error is:
In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 134 - 5.84 = 128.16 calories
The upper end of the interval is the sample mean added to M. So it is 134 + 5.84 = 139.84 calories
The 95% confidence interval of for this random sample is between 128.16 calories and 139.84 calories. This means that we are 95% that the mean number of calories for all bags of potato chips is in this interval.
Answer: Last option
(42÷2) +5
Step-by-step explanation:
We know that Mr. Roberts drove 42 miles on Monday.
On Tuesday Mr. Roberts drove half of what he drove on Monday plus 5 miles.
If we want to know how many miles Mr. Roberts drove on Tuesday then we should divide 42÷2 to find half of 42.
Then we know that in addition to the 21 miles he drove 5 more miles. Then we add 21 +5 = 26 miles.
So the expression that gives us the number of miles that Mr. Roberts drove on Tuesday is:
(42÷2) +5