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oksian1 [2.3K]
2 years ago
10

Which is part of the process in the formation of hail pellets? They are tossed up and down in clouds. They lose layers of ice an

d grow smaller. They grow to less than 5 mm in diameter. They form ice crystals directly from water vapor.
Mathematics
1 answer:
kondaur [170]2 years ago
3 0

Answer:

they are tossed up and down in clouds

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Joanna went school supply shopping. She spent $29.16 on notebooks and pencils. Notebooks cost $1.88 each and pencils cost $1.36
Sati [7]

Answer:

its c

Step-by-step explanation:

8 0
3 years ago
Find the roots of h(t) = (139kt)^2 − 69t + 80
Sonbull [250]

Answer:

The positive value of k will result in exactly one real root is approximately 0.028.

Step-by-step explanation:

Let h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80, roots are those values of t so that h(t) = 0. That is:

19321\cdot k^{2}\cdot t^{2}-69\cdot t + 80=0 (1)

Roots are determined analytically by the Quadratic Formula:

t = \frac{69\pm \sqrt{4761-6182720\cdot k^{2} }}{38642}

t = \frac{69}{38642} \pm \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321}  }

The smaller root is t = \frac{69}{38642} - \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321}  }, and the larger root is t = \frac{69}{38642} + \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321}  }.

h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80 has one real root when \frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} = 0. Then, we solve the discriminant for k:

\frac{80\cdot k^{2}}{19321} = \frac{4761}{1493204164}

k \approx \pm 0.028

The positive value of k will result in exactly one real root is approximately 0.028.

7 0
3 years ago
Find the amount of time. I=$237.90, P=$1525, r=2.6%<br><br> think I=PRT
egoroff_w [7]
AWNER is 6

Hope it helps u
7 0
3 years ago
Drag each tile to the correct box. not all tiles will be used.Chris plans to mulch the border surrounding a rectangular garden i
amm1812

Length (L): 2w + 3

width (w): w

border (b): \frac{1}{4} w

Area (A) = (L + b) * (w + b)   <em>NOTE: This is assuming the width also has a border</em>

              = (2w + 3 + \frac{1}{4} w) * (w + \frac{1}{4} w)

              = (2\frac{1}{4} w + 3)(1\frac{1}{4} w)

              = (\frac{9}{4} w + 3)(\frac{5}{4} w)

              = \frac{45}{16} w^2 + \frac{15}{4}w


5 0
3 years ago
Can someone help me please thank you
Blizzard [7]

<em>Di </em><em>ko </em><em>alam </em><em>Yan </em><em>sorry </em>

Step-by-step explanation:

Bobo ako eh ML nalng Joke lang Tanong nalng kayo Ng iba

4 0
3 years ago
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