Answer:
y = 32
Step-by-step explanation:
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Answer:
The dimensions are x =20 and y=20 of the garden that will maximize its area is 400
Step-by-step explanation:
Step 1:-
let 'x' be the length and the 'y' be the width of the rectangle
given Jenna's buys 80ft of fencing of rectangle so the perimeter of the rectangle is 2(x +y) = 80
x + y =40
y = 40 -x
now the area of the rectangle A = length X width
A = x y
substitute 'y' value in above A = x (40 - x)
A = 40 x - x^2 .....(1)
<u>Step :2</u>
now differentiating equation (1) with respective to 'x'
........(2)
<u>Find the dimensions</u>
<u></u><u></u>
40 - 2x =0
40 = 2x
x = 20
and y = 40 - x = 40 -20 =20
The dimensions are x =20 and y=20
length = 20 and breadth = 20
<u>Step 3</u>:-
we have to find maximum area
Again differentiating equation (2) with respective to 'x' we get
Now the maximum area A = x y at x =20 and y=20
A = 20 X 20 = 400
<u>Conclusion</u>:-
The dimensions are x =20 and y=20 of the garden that will maximize its area is 400
<u>verification</u>:-
The perimeter = 2(x +y) =80
2(20 +20) =80
2(40) =80
80 =80
99 km ... 9 liters
x km ... 12 liters
If the relationship is proportional, we have
from where
The answer is 132 kilometers.
x km ... 12 liters
If the relationship is proportional, we have
from where
The answer is 132 kilometers.
let's bear in mind that sin(θ) in this case is positive, that happens only in the I and II Quadrants, where the cosine/adjacent are positive and negative respectively.