3 years ago

Hey i’ll give brainliest please help

Mathematics

1 answer:

just olya [345]3 years ago

7 0

I believe the answer is the fourth option.

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How do you solve this????

riadik2000 [5.3K]

I got 14 for the answer

4 0

3 years ago

PLEASE I REALLY NEED HELP!

vagabundo [1.1K]

Answer:

$\frac{3}{28}$

Step-by-step explanation:

Probability (P) is calculated as

P = $\frac{requiredoutcome}{count}$

The first required outcome is a red sweet from a total of 3 + 5 = 8

P( red) = $\frac{3}{8}$

There are now 2 red left and a count of 7, since 1 has been eaten, thus

P( second red ) = $\frac{2}{7}$

P( red and red ) = $\frac{3}{8}$ × $\frac{2}{7}$ = $\frac{6}{56}$ = $\frac{3}{28}$

6 0

3 years ago

20. What is the greatest prime factor of 3^7+6^6 ?

mario62 [17]

Answer:

Step-by-step explanation:

3^7 = 2187

6^6 = 46656

46656+2187=48843

Prime factors of 48843: 3, 3, 3, 3, 3, 3, 67

Factor tree:

48843

| \

16281 3

| \

5427 3

| \

1809 3

| \

603 3

| \

201 3

| \

67 3

3 0

2 years ago

Given the functions f(x) = − 4x − 1 and g(x) = 2x + 4, which operation results in the smallest coefficient on the x term?

Sedbober [7]

F(x)=-4x-1 if you sub 3 into it you get 3(-4)-1 which is -13 and 2x+4=10

4 0

3 years ago

Read 2 more answers

How many digits are written when 1000 to the power of 2015 is expressed as a numeral?

PtichkaEL [24]

Answer: There are 6046 digits will be written on expansion upto 2015th power.

Step-by-step explanation:

Since we have given that

$1000^{2015}$

We have to find the number of digits ,

So,

$1000^{2015}\\\\=(10^3)^{2015}\\\\=10^{6045}$

Since we know that

$10^n\text{ has n+1 number of digits }$

so,

$10^{6045}\text{ has 6046 number of digits }$

Hence, there are 6046 digits will be written on expansion upto 2015th power.

6 0

3 years ago