All categories

2 years ago

Hey i’ll give brainliest please help

Mathematics

1 answer:

just olya [345]2 years ago

7 0

I believe the answer is the fourth option.

You might be interested in

Find the greatest common factor of 15x^2y^3 and -18x^3yz The Answer has to be like _x_y_

Daniel [21]

Answer:

The greatest common factor of this would be 3x^2y

Step-by-step explanation:

In order to find this, first find the greatest common factor of the coefficients. Since 3 goes in evenly to both 15 and -18, then we know that it is a common factor.

From there we need to find the number of x's. Since the first term only has 2 x's and the second has 3, we take the lowest number. (x^2)

And since the first term has 3 y's and the second has just 1, we take the lowest number (y).

8 0

3 years ago

13. f(x) = x + 5 a. f(4) b. f(7) c. f(-3) d. f(0) e. f(2.4) f. f(2/3)

SashulF [63]

A.9
B.12
C.2
D.5
E.7.4
F.5 2/3 or 5.6666

4 0

3 years ago

What is the largest possible integral value in the domain of the real-valued function

kotegsom [21]

Answer:

Max Value: x = 400

General Formulas and Concepts:

Algebra I

Domain is the set of x-values that can be inputted into function f(x)

Calculus

Antiderivatives
Integral Property: $\int {cf(x)} \, dx = c\int {f(x)} \, dx$
Integration Method: U-Substitution
[Integration] Reverse Power Rule: $\int {x^n} \, dx = \frac{x^{n+1}}{n+1} + C$

Step-by-step explanation:

Step 1: Define

$f(x) = \frac{1}{\sqrt{800-2x} }$

Step 2: Identify Variables

Using U-Substitution, we set variables in order to integrate.

$u = 800-2x\\du = -2dx$

Step 3: Integrate

Define: $\int {f(x)} \, dx$
Substitute: $\int {\frac{1}{\sqrt{800-2x} } } \, dx$
[Integral] Int Property: $-\frac{1}{2} \int {\frac{-2}{\sqrt{800-2x} } } \, dx$
[Integral] U-Sub: $-\frac{1}{2} \int {\frac{1}{\sqrt{u} } } \, du$
[Integral] Rewrite: $-\frac{1}{2} \int {u^{-\frac{1}{2} }} \, du$
[Integral - Evaluate] Reverse Power Rule: $-\frac{1}{2}(2\sqrt{u}) + C$
Simplify: $-\sqrt{u} + C$
Back-Substitute: $-\sqrt{800-2x} + C$
Factor: $-\sqrt{-2(x - 400)} + C$

Step 4: Identify Domain

We know from a real number line that we cannot have imaginary numbers. Therefore, we cannot have any negatives under the square root.

Our domain for our integrated function would then have to be (-∞, 400]. Anything past 400 would give us an imaginary number.

7 0

2 years ago

6 - 2x = 6x - 10x + 4

yarga [219]

$6 - 2x = 6x - 10x + 4$

$6 - 2x = - 4x + 4$

$6 = - 4x + 4 + 2x$

$6 = - 2x + 4$

$- 2x + 4 = 6$

$- 2x = 6 - 4$

$- 2x = 2$

$x = \frac{ \: \: \: 2}{ - 2}$

$x = - 1$

Therefore , the value of x = -1

6 0

2 years ago

What is the value of this expression? 100 - [(5 x 3 + 4)]

shepuryov [24]

Answer:

Step-by-step explanation:

Order of operations rules require that we do the work inside parentheses first. Multiplication must be done before addition. Thus, the quantity inside parentheses becomes 15 + 4 = 19.

Next, we evaluate 100 - [19], obtaining 81 (answer)

7 0

3 years ago

Read 2 more answers