H = 2sqrt2
D = 6sqrt3
In a 45,45,90 triangle the hypotenuse is (x)sqrt2 while the side lengths are equivalent being a single value x. Therefore, when given the hypotenuse and solving for the leg, divide 4 by sqrt2 to get 4sqrt2/2 which simplifies to 2sqrt2 when the denominator and numerator cancel.
In a 30,60,90 triangle the short leg x is across from the 30 degree angle meaning the angle across from the 60 degree angle is x times the sqrt of 3. Therefore the long leg is 6sqrt3
Answer:
Step-by-step explanation:
The relative frequency of it landing on tails is 20/30 or 2/3 or 0.667
the answer is 126
200 divided by 100 = 2
2 x 7= 14
14 x 9 = 126
When using the Law of Sines the ambiguous case can result.
Source:
http://www.1728.org/trigtut2.htm
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